## PROBLEMS ON SURFACE AREA OF CYLINDER

Curved surface area of cylinder is the measurement of outer area,  where the extension of top and bottom portion wont be included.

## Curved surface area of cylinder

If a rectangle revolves about one side and completes one full rotation, the solid thus formed is called a right circular cylinder. The above picture shows that how rectangle forms a right circular cylinder. In other words curved surface area is simply said as CSA

CSA of cylinder = 2 π r h

"r" and "h" stands for radius and height of cylinder.

## Curved surface area of hollow cylinder

A hollow cylinder is a three dimensional solid bounded by two parallel cylindrical surfaces and by two parallel circular bases cut out from two parallel planes by these two cylindrical surfaces.

CSA of hollow cylinder = 2πh(R+r)

R  =  external radius, r = internal radius and h  =  height

Example 1 :

The external surface area of a hollow cylinder is 540Π cm2.Its internal diameter is 16 cm and height is 15 cm. Find the curved surface area.

Solution :

External surface area of cylinder  =  540 Π cm²

2 Π R h  =  540 Π cm²

Internal radius (r)  =  16/2  =  8 cm

height (h)  =  15 cm

2 Π  R ⋅ h  =  540 Π

Π R15  =  540 Π

=  540 Π  (1/2)  (1/Π)  (1/15)

=  270/(15)

R  =  18

Curved surface area =  2 Π h (R + r)

=  2Π(15)(18+8)

=  390Π cm2

Curved surface area of the cylinder  =  390Π cm2

Example 2 :

The external diameter of the cylindrical shaped iron pipe is 25 cm and its length is 20 cm. If the thickness of the pipe is 1 cm, find the curved surface area of the pipe.

Solution :

External radius of the pipe (R)  =  12.5 cm

height of the pipe (h)  =  20 cm

thickness of the pipe (w)  =  1 cm

To find curved surface area of the cylinder, we have to find the internal radius (r)

W = R - r

1  =  12.5 - r

r  =  12.5 - 1

r  =  11 .5 cm

Curved surface area  =  2 Π h (R + r)

=  2 Π (20) (12.5 + 11.5)

=  960 Π cm2

Hence curved surface area of cylinder is 960 Π cm2.

Example 3 :

The radii of two right circular cylinders are in the ratio 3:2 and their heights are in the ratio 5:3. Find the ratio of their curved surface areas.

Solution :

Let r1 , r2 and h1, h2 are radii and heights of first and second cylinders respectively.

Now we have to find the ratio of  their curved surface areas

Curved surface area of cylinder  =  2Πrh

Curved surface area of first cylinder  =  2Πr1h1

Curved surface area of second cylinder  =   2Πr2h2

r1 : r2  =  3:2

r1/r2  =  3/2

r1  =  3r2/2

h: h2 = 5 : 3

h1/h2  =  5/3

h1  =  5h2/3

Ratios of curved surface area of two cylinders

r1hr2h2

(3r2/2) (5h2/3) :  r2 : h

=  5/2 : 1

=  5 : 2

So, ratio of their curved surface areas is 5 : 2.

Example 4 :

The diameter of the road roller of length 120 cm is 84 cm. If it takes 500 complete revolutions to level play ground, then find the cost of leveling it at the cost of \$ 1.5 per square meter.

Solution :

Radius of cylinder (r)  = 84/2

r  =  42 cm

height of cylinder (h) = 120 cm

Area covered by road roller in one revolution = CSA of the road roller

Curved surface area of cylinder = 2 Π r h

=  2  ⋅ (22/7)  42  120

=  31680 cm2

Area covered by 500 revolutions  =  500 x 31680

=  15840000 cm2

=  1584 m2

Cost of leveling per square meter  =  \$1.5

Required cost  =  1584 x 1.5

=  \$2376

So, required cost is \$ 2376.

Example 5 :

The internal and external radii of of a hollow cylinder are 12 cm and 18 cm respectively. If its height is 14 cm, then find its curved surface area.

Solution :

External radius (R)  =  18 cm

Internal radius (r)  =  12 cm

height (h)  =  14 cm

Curved surface area  =  2Πh (R+r)

=  2  (22/7) (14) (18 + 12)

=  2640 cm2

So, curved surface area of cylinder is 2640 cm2

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