# PROBLEMS ON SUPPLEMENTARY ANGLES

## About "Problems on Supplementary angles"

On this web page, we are going to have  problems on supplementary angles.

Before that, do you want to know the basic stuff about "complementary and supplementary angles" ?,

Now, let us look at some problems on supplementary angles.

Example 1 :

The measure of an angle is 108°. What is the measure of a supplementary angle?

Solution :

Let "x" be the measure of a supplementary angle required.

Since "x" and 108° are supplementary angles, we have

x + 108° = 180°

x = 180° - 108°

x = 72°

Hence the measure of the supplementary angle is 72°

Example 2 :

The measure of an angle is 89°. What is the measure of a supplementary angle?

Solution :

Let "x" be the measure of a supplementary angle required.

Since "x" and 41° are supplementary angles, we have

x + 89° = 180°

x = 180° - 89°

x = 91°

Hence the measure of the supplementary angle is 91°

Example 3 :

Two angles are supplementary. If one angle is two times the sum of other angle and 3, find the two angles.

Solution :

Let "x" and "y" be the two angles which are complementary.

So, we have x + y = 90° --------> (1)

From the information, "one angle is two times the sum of other angle and 3", we have

x = 2(y+3)

x = 2y + 6 ------->(2)

Now plug x = 2y + 6 in equation (2)

(1)-------> 2y + 6 + y  = 90

3y + 6 = 90

3y = 84

y = 28

Now, plug y = 28 in equation (2).

(2) --------> x = 2(28) + 6

x = 56 + 6

x = 62

Hence the two angles are 62° and 28°

Example 4 :

Two angles are supplementary. If one angle is 36° less than twice of the other angle, find the two angles.

Solution :

Let "x" and "y" be the two angles which are supplementary.

So, we have  x + y = 180° ----------->(1)

From the information, "one angle is 36

From the information, "one angle is 36° less than twice of the other angle", we have

x = 2y - 36 ----------->(2)

Now plug x = 2y - 36 in equation (1)

(1)-------> 2y - 36 + y  = 180

3y - 36 = 180

3y = 216

y = 72

Now, plug y = 72 in equation (2).

(2) --------> x = 2(72) - 36

x = 144 - 36

x = 108

Hence the two angles are 108° and 72°

Hence the required angle is 60°

Example 5 :

Two angles are supplementary. If 5 times of one angle is 10 times of the other angle. Find the two angles.

Solution :

Let "x" and "y" be the two angles which are supplementary.

So, we have x + y = 180° -------->(1)

From the information, "5 times of one angle is 10 times of the other angle", we have

5x = 10y  =====> x = 2y ---------(2)

Plug x = 2y in equation (1)

2y + y = 180

3y = 180

y = 60

Plug y = 60 in equation (2)

x = 2(60)

x = 120

Hence the two angles are 60° and 120°.

Example 6 :

Find the value of  "x" in the figure given below. Solution :

From the picture above, it is very clear that (2x+3) and (x-6) are  supplementary angles.

So, we have (2x+3) + (x-6)  = 180°

2x + 3 + x - 6 = 180°

3x - 3 = 180

3x = 183

x = 61

Hence the value of "x" is 61.

Example 7 :

Find the value of  "x" in the figure given below. Solution :

From the picture above, it is very clear (5x+4), (x-2) and (3x+7) are supplementary angles.

So, we have (5x+4) + (x-2) + (3x+7) = 180°

5x + 4 + x -2 + 3x + 7 = 180°

9x + 9 = 180

9x = 171

x = 19

Hence the value of "x" is 19

After having gone through the problems on supplementary angles,  we hope that the students would have understood "How to do problems on supplementary angles". 