**Problems on Average : **

In this section, we are going to see, how average problems in quantitative aptitude can be solved easily.

The formula given below can be used to find average of the given values.

**Example 1 : **

Find the average of first 20 natural numbers which are divisible by 7.

**Solution : **

**Step 1 : **

The first natural number which is divisible by 7 is 7.

The next numbers which are divisible by 7 are 14, 21..... **Step 2 : **

Write the first twenty natural numbers which are divisible by 7.

They are 7,14,21,28........ up to 20 terms. **Step 3 : **

Find the sum of all the above numbers.

= 7+14+21+28.........up t0 20 term

Because all of the above numbers are divisible by 7, we can factor 7.

= 7(1+2+3+4+.........+20)

Therefore, sum = 7(210)

**Step 4 : **

Find the average.

Average = (sum of all 20 numbers)/20

Average = (7⋅210)/20

Average = 73.5

Hence average of first 20 natural numbers which are divisible by 7 is 73.5

**Example 2 :**

The average of four consecutive even numbers is 27. Find the largest of these numbers.

**Solution : **

**Step 1 :**

Let "x' be the first even number.

Then the four consecutive even numbers are

x, x+2, x+4, x+6.

**Step 2 :**

Average of the four consecutive even numbers = 27

So, we have

(x+x+2+x+4+x+6) / 4 = 27

(4x + 12) = 108

4x = 96 ===> x = 24

Hence the largest even number = (x + 6) = 30.

**Example 3 :**

There are two sections A and B of a class, consisting 36 and 44 students respectively. If the average weight of the section A is 40 kg and that of section B is 35 kg, find the average weight of the whole class.

**Solution : **

**Step 1 :**

For section A, average weight = 40 kg.

That is,

(sum of the weights of 36 students) / 36 = 40

Sum of the weights of 36 students = 1440.

**Step 2 :**

For section B, average weight = 35 kg.

That is,

(sum of the weights of 44 students) / 44 = 35

Sum of the weights of 44 students = 1540.

**Step 3 :**

Total weight of 80 students (whole class) is

= 1440 + 1540

= 2980

**Step 4 : **

Find the average weight of the whole class.

Average weight of the whole class is

= Total weight / No. of students

= 2980/80

= 37.25 kg

Hence, the average weight of the whole class is 37.25 kg.

**Example 4 :**

In John's opinion, his weight is greater than 65 kg but less than 72 kg. His brother doesn't agree with John and he thinks that John's weight is greater than 60 kg but less than 70 kg. His mother's view is that his weight cannot be greater than 68 kg. If all are them are correct in their estimation, what is the average of different probable weights of John ?

**Solution : **

Let "x" be John's weight

**Step 1 :**

According to John, we have 65 < x < 72.

According to his brother, we have 60 < x < 70.

According to his mother, we have x ≤ 68.

**Step 2 :**

The values of "x" which satisfy all the above three conditions are 66, 67 and 68.

**Step 3 :**

Average of the above three values is

= Sum of the three values / 3

= (66+67+68) / 3

= 201/3

= 67

Hence, the average of different probable weights of John is 67 kg

**Example 5 :**

A batsman makes a score of 87 runs in the 17th match and thus increases his average by 3. Find the average score average after 16th match.

**Solution : **

**Step 1 :**

Let "x" be the average after 16^{th} match.

Then, the average after 17^{th} match is (x + 3).

**Step 2 :**

Average after 17 matches = x + 3

(Total runs scored in 17 matches) / 17 = x + 3

Total runs scored in 17 matches = 17(x + 3)

Total runs scored in 17 matches = 17x + 51 ----- (1)

**Step 3 :**

Average after 16 matches = x

(Total runs scored in 16 matches) / 16 = x

Total runs scored in 16 matches = 16x

Given : Runs cored in 17th match = 87

Then, total runs scored in 17 matches = 16x + 87 -----(2)

**Step 4 :**

From (1) and (2),

17x + 51 = 16x + 87

Subtract 16x from both sides.

x + 51 = 87

Subtract 51 from both sides.

x = 36

Hence, the average score after 16th match is 36.

After having gone through the stuff given above, we hope that the students would have understood "Problems on Average"

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