PROBLEMS ON AGES

About "Problems on Ages"

Problems on Ages :

In this section, we are going to see, how problems on ages can be solved.

Problems on Ages - Practice Questions

Question 1 :

The age of a man is three times the sum of the ages of his two sons and 5 years hence his age will be double the sum of their ages. Find the present age of the man.

Solution :

Let "x" be the present age of the man and "y" be the sum of the present ages of two sons.

Given : Present age of the man is 3 times the sum of the ages of 2 sons

Then, we have

x = 3y -----(1)

Given : 5 years hence, age of the man will be double the sum of the ages of his two sons.

Then, we have

x + 5 = 2(y + 5 + 5)

(Here, 5 is added twice to y. Because, there are two sons in y)

x + 5 = 2(y + 10)

x + 5 = 2y + 20

From (1), we can plug x = 3y.

3y + 5 = 2y + 20

y = 15

Plug y = 15 in (1).

(1)-----> x = 3 ⋅ 15

x = 45

Hence the present age of the man is 45 years.

Question 2 :

Present age of a father is 3 years more than three times the age of his son. Three years hence, father's age will be 10 years more than twice the age of the son. Find the present age of the father.

Solution :

Let "x" be the present age of the son and "y" be the present age of the father. .

Given : Present age of a father is 3 years more than three times the age of his son.

Then, we have

y = 3x + 3 -----(1)

Given : Three years hence, father's age will be 10 years more than twice the age of the son.

Then, we have

y + 3 = 2(x + 3) + 10

y + 3 = 2x + 6 + 10

y + 3 = 2x + 16

From (1), we can plug y = 3x + 3.

3x + 3 + 3 = 2x + 16

3x + 6 = 2x + 16

x = 10

Plug x = 10 in (1).

(1)-----> y = 3 ⋅ 10 + 3

y = 33

Hence the present age of the man is 33 years.

Question 3 :

The ratio of the age of a man and his wife is 4 : 3. After 4 years this ratio will become 9 : 7. At the time of marriage, if the ratio was 5 : 3, how many years ago were they married ?

Solution :

Given : The ratio of the present ages of a man and his wife is 4 : 3

Then, the present age of the man is 4x and his wife is 3x.

Given : After 4 years this ratio will become 9 : 7.

Then, we have

(4x + 4) : (3x + 4) = 9 : 7

(4x + 4) / (3x + 4) = 9 / 7

7(4x + 4) = 9(3x + 4)

28x + 28 = 27x + 36

x = 8

So, the present age of the man is

= 4x

= 4 ⋅ 8

= 32 years

The present age of his wife is

= 3x

= 3 ⋅ 8

= 24 years

Let us assume that they got married before "t" years from now.

Given : At the time of marriage, if the ratio was 5 : 3

Then, we have

(32 - t) : (24 - t) = 5 : 3

(32 - t) / (24 - t) = 5 / 3

3(32 - t) = 5(24 - t)

96 - 3t = 120 - 5t

2t = 24

t = 12

Hence, they got married 12 years before.

Question 4 :

John's age after six years will be three seventh of his father's age. Ten years ago the ratio of their ages was 1 : 5 . What is John's father's age at present ?

Solution :

Given : Ten years ago the ratio of their ages was 1 : 5

Then, ten years ago,

Age of John = x

Age of his father = 5x

At present,

Age of John = x + 10

Age of his father = 5x + 10

After six years,

Age of John = x + 10 + 6 = x + 16

Age of his father = 5x + 10 + 6 = 5x + 16

Given : John's age after six years will be three seventh of his father's age.