**Point of concurrency :**

We know that two non parallel lines intersect at a point. If a third line is drawn passing through the same point, these straight lines are called concurrent-lines.

In the figure given below, the straight lines AB, CD and EF are passing through one point "P".

Here point "P" is the point-of concurrency.

**Question 1 : **

From the figure given below, find out the concurrent-lines and point-of concurrency.

**Solution :**

The straight lines AB, CD, PQ and RS are concurrent lines. These lines are passing through the point "O".

Therefore "O" is the point-of concurrency.

**Question 2 :**

Prove that the lines 3x - 4y + 5 = 0, 7x - 8y + 5 = 0 and 4x + 5y = 45 are concurrent and also find the point-of concurrency.

**Solution : **

Let

3x - 4y + 5 = 0 -------- (1)

7x - 8y + 5 = 0 -------- (2)

4x + 5y = 45 -------- (3)

Let us solve the equations (1) and (2) using substitution method as given below.

(1) -----> 3x + 5 = 4y or **4y = 3x + 5**

(2) -----> 7x -8y + 5 = 0 or **7x - 2(4y) + 5 = 0**

Now, plug 4y = 3x + 5

7x - 2(3x + 5) + 5 = 0

7x - 6x - 10 + 5 = 0

x - 5 = 0

x = 5

Now, plug x = 5 in 4y = 3x + 5

4y = 3(5) + 5

4y = 20

y = 5

So, the point of intersection of lines (1) and (2) is (5, 5).

Now let us check that whether the third line satisfies the point (5,5).

To do that, plug (5, 5) in the equation of the third line.

That is, 4x + 5y = 45

(3) ------> 4(5) + 5(5) = 45

20 + 25 = 45

45 = 45

Point of intersection of lines (1) and (2) satisfies the third line.

**Therefore, all the given three lines are passing through the same point (5,5) and they are concurrent. **

**And the point of concurrency is (5,5)**

After having gone through the stuff given above, we hope that the students would have understood "Point-of concurrency".

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