The perpendicular distance from the point (x1, y1) to the line ax + by + c = 0 is
|(ax1 + by1 + c) / √[a2 + b2]|
Example 1:
Find the length of the perpendicular from (2, -3) to the straight line 2x - y + 9 = 0
Solution :
The length of the perpendicular from the point (x1, y1) to the line ax + by + c = 0 is
|(ax1 + by1 + c) / √[a2 + b2]|
Substitute.
= |[2(2) - (-3) + 9] / √[22 + (-1)2]|
= |(4 + 3 + 9) / √(4 + 1)|
= |16/√5|
= 16/√5 units
Example 2 :
Find the length of the perpendicular from (5,2) to the straight line 3x + 2y - 1 = 0
Solution :
The length of the perpendicular from the point (x1, y1) to the line ax + by + c = 0 is
|(ax1 + by1 + c) / √[a2 + b2]|
Substitute.
= |[3(5) + 2(2) - 1] / √[32 + 22]|
= |[15 + 4 - 1] / √[9 + 4]|
= |18/√13|
= 18/√13 units
Example 3 :
Find the length of the perpendicular from (0,1) to the straight line x - 3y + 2 = 0
Solution :
The length of the perpendicular from the point (x1, y1) to the line ax + by + c = 0 is
|(ax1 + by1 + c) / √[a2 + b2]|
Substitute.
= |[1(0) - 3(1) + 2] / √[12 + (-3)2]|
= |[0 - 3 + 2] / √[1 + 9]|
= |-1/√10|
= 1/√10 units
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