**Perimeter of a triangle :**

Here we are going to see example problems to find the perimeter of triangle.

Formula:

Let a, b and c is the sides of the triangle. Then the perimeter

**P = a + b + c**

Now let us see some example problems to understand this concept much better.

**Example 1:**

The sides of a triangle are 12 cm, 6 cm and 8 cm.find the perimeter of the triangle.

**Solution : **

Let a, b and c are the three sides of the triangle

a = 12 cm, b = 6 cm and c = 8 cm

Perimeter P = 12 + 6 + 8

= 26 cm

Hence, the perimeter of a required triangle is 26 cm

**Example 2 : **

The sides of a triangle are 5 cm; 7 cm and 9 cm find the perimeter of the triangle.

**Solution :**

Let a, b and c are the three sides of the triangle

a = 5 cm, b = 7 cm and c = 9 cm

Perimeter P = 5 + 7 + 9

= 21 cm

Therefore the perimeter of a required triangle = 21 cm**Example 3 :**

The sides of a triangle are in the ratio 2x, 3x and 5x. If the
perimeter of the triangle is 100 then find the measurement of three
sides.

**Solution :**

Let a, b and c be the three sides of the triangle

a = 2x, b = 3x and c = 5x

Perimeter P = 2x + 3x + 5x = 10 x

Perimeter of triangle = 100 cm

10 x =100

x = 100/10

x = 10 cm

Therefore a = 2x = 2(10) = 20 cm

b = 3x = 3(10) = 30 cm

c = 5x = 5(10) = 50 cm

- Length of arc
- Practice questions on length of arc
- Perimeter of Sector
- Perimeter of square
- Perimeter of parallelogram
- Perimeter of rectangle
- Area of a circle
- Area of Semicircle
- Area of Quadrant
- Area of sector
- Area of triangle
- Area of equilateral triangle
- Area of scalene triangle
- Area of square
- Area of rectangle
- Area of parallelogram
- Area of rhombus
- Area of trapezium
- Area of quadrilateral
- Area around circle
- Area of pathways
- Area of combined shapes

After having gone through the stuff given above, we hope that the students would have understood "Area of a triangle"

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