Problem 1 :
Find the perimeter of the square having side length 14 cm.
Problem 2 :
If the perimeter of square is 32 inches, then find the length of each side.
Problem 3 :
The square has side length 250 cm. Find its perimeter in meter.
Problem 4 :
The length of each side of a square is 48 inches. Find its perimeter in feet.
Problem 5 :
If the length of each diagonal of a square is 2√2 cm, then find its perimeter.
Problem 6 :
If the area of a square is 49 square inches, then find its perimeter.
Problem 7 :
Find the perimeter of the figure which has the following vertices in xy-coordinate plane.
E(-1, 3), F(4, 3), G(4, -2) and H(-1, -2)
Problem 8 :
PQ is one of the sides of the square PQRS and the side PQ is defined by P(0, 2) and Q(6, 9). Find the perimeter of the square PQRS.
Problem 9 :
AC is one of the diagonals of the square ABCD and the diagonal AC is defined by A(1, 4) and C(4, 8). Find the perimeter of the square ABCD.
Problem 10 :
If the lengths of the sides of two squares are in the ratio 2 : 5. then find the ratio of their perimeters.
Problem 1 :
Find the perimeter of the square having side length 14 cm.
Solution:
Formula for perimeter of a square :
= 4s
Substitute 14 for s.
= 4(14)
= 56
So, the perimeter of the square is 56 cm.
Problem 2 :
If the perimeter of square is 32 inches, then find the length of each side.
Solution:
Perimeter of the square = 32 inches
4s = 32
Divide each side by 4.
s = 8
So, the length of each side of the square is 8 inches.
Problem 3 :
The square has side length 250 cm. Find its perimeter in meter.
Solution:
Formula for perimeter of a square :
= 4s
Substitute 250 for s.
= 4(250)
= 1000 cm -----(1)
We know
100 cm = 1 m
Therefore, to convert centimeter into meter, we have to divide by 100.
(1)-----> Perimeter = 1000 cm
Divide the right side by 100 to convert cm into m.
Perimeter = (1000 / 100) m
= 10 m
So, the perimeter of the square is 10 meters.
Problem 4 :
The length of each side of a square is 48 inches. Find its perimeter in feet.
Solution :
Formula for perimeter of a square :
= 4s
Substitute 48 for s.
= 4(48)
= 192 inches -----(1)
We know
12 inches = 1 ft
Therefore, to convert inches into feet, we have to divide by 12.
(1)-----> Perimeter = 192 inches
Divide the right side by 12 to convert inches into ft.
Perimeter = (192 / 12) ft
= 16 ft
So, the perimeter of the square is 16 ft.
Problem 5 :
If the length of each diagonal of a square is 2√2 cm, then find its perimeter.
Solution:
To find the perimeter of a square, first we have to know the length of each side.
Let s be the length of each side of the square.
Draw a sketch.
In the figure shown above, consider the right triangle ABC.
By Pythagorean Theorem, we have
AB2 + BC2 = AC2
Substitute.
s2 + s2 = (2√2)2
Simplify and solve for s.
2s2 = 22 ⋅(√2)2
2s2 = 4 ⋅(2)
2s2 = 8
Divide each side by 2.
s2 = 4
Find positive square root on both sides.
√s2 = √4
√s2 = √(2 ⋅ 2)
s = 2
Formula for perimeter of a square.
Perimeter = 4s
Substitute 2 for s.
= 4(2)
= 8
So, the perimeter of the the square is 8 cm.
Problem 6 :
If the area of a square is 49 square inches, then find its perimeter.
Solution:
Area of the square = 49 square inches
s2 = 49
Find positive square root on both sides.
√s2 = √49
√s2 = √(7 ⋅ 7)
s = 7
Formula for perimeter of a square :
= 4s
Substitute 7 for s.
= 4(7)
= 28
So, the perimeter of the square is 28 inches.
Problem 7 :
Find the perimeter of the figure which has the following vertices in xy-coordinate plane.
E(-1, 3), F(4, 3), G(4, -2) and H(-1, -2)
Solution:
Draw a sketch with the given vertices.
Clearly, the above figure is a square with side length of 5 units.
Formula for perimeter of a square :
= 4s
Substitute 5 for s.
= 4(5)
= 20
So, the perimeter of the square is 20 units.
Problem 8 :
PQ is one of the sides of the square PQRS and the side PQ is defined by P(0, 2) and Q(6, 9). Find the perimeter of the square PQRS.
Solution:
Distance between the two points (x1, y1) and (x2, y2) is
= √[(x2-x1)2+(y2-y1)2]
To find the distance between P and Q, substitute
(x1, y1) = (0, 2)
(x2, y2) = (6, 9)
in the above formula.
Distance between P and Q :
= √[(6-0)2 + (9-2)2]
= √[62 + 72]
= √[36 + 49]
= √85
Therefore, the length of one of the sides is √85 units.
Formula for perimeter of a square :
= 4s
Substitute s = √85.
= 4√85
Use calculator and simplify.
≈ 36.88
So, the perimeter of the square PQRS is about 36.88 units.
Problem 9 :
AC is one of the diagonals of the square ABCD and the diagonal AC is defined by A(1, 4) and C(4, 8). Find the perimeter of the square ABCD.
Solution :
Distance between the two points (x1, y1) and (x2, y2) is
= √[(x2-x1)2+(y2-y1)2]
To find the distance between A and C, substitute
(x1, y1) = (1, 4)
(x2, y2) = (4, 8)
in the above formula.
Distance between A and C :
= √[(4-1)2 + (8-4)2]
= √[32 + 42]
= √[9 + 16]
= √25
= 5
Therefore, the length of the diagonal AC is 5 units.
To find the perimeter of a square, first we have to know the length of each side.
Let s be the length of each side of the square.
Draw a sketch.
In the figure shown above, consider the right triangle ABC.
By Pythagorean Theorem, we have
AB2 + BC2 = AC2
Substitute.
s2 + s2 = 52
Simplify and solve for s.
2s2 = 25
Divide each side by 2.
s2 = 12.5
Find positive square root on both sides.
√s2 = √12.5
s = √12.5
Formula for perimeter of a square.
Perimeter = 4s
Substitute √12.5 for s.
= 4√12.5
Use calculator and simplify.
≈ 14.14
So, the perimeter of the the square is about 14.14 units.
Problem 10 :
If the lengths of the sides of two squares are in the ratio 2 : 5. then find the ratio of their perimeters.
Solution:
From the ratio 2 : 5, let the sides of two squares be 2x and 5x respectively.
Formula for perimeter of a square :
= 4s
Perimeter of 1st square = 4(2x) = 8x |
Perimeter of 1st square = 4(5x) = 10x |
Ratio of the perimeters :
= 8x : 10x
Divide each term by 2x.
= 2 : 5
So, the ratio of the perimeters of two squares is 2 : 5.
Note :
The ratio of the sides of two squares and the ratio of the perimeters of two squares are same.
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