PERCENTS OF NUMBERS WORD PROBLEMS
To solve percents of numbers word problems we need to follow the steps given below :
(i) Understand the given question.
(ii) Identify that what we have to find out from the given question.
(iii) Use the formula.
Problem 1 :
There are 250 students in a school. 55 students like basketball, 75 students like football, 63 students like throw ball, while the remaining like cricket. What is the percent of students who like (a) basket ball? (b) throw ball?
Solution :
Total number of students is 250.
(a) Number of students who like basket ball is 55.
55 out of 250 like basket ball which can be represented as 55/250.
Percentage of students who like basket ball
= (55 / 250) ⋅ 100%
= 22%
(b) Number of students who like throw ball is 63.
63 out of 250 like throw ball and that can be represented as 63/250
Percentage of students who like throw ball
= (63 / 250) ⋅ 100%
= (126 / 5)%
= 25.2%
22% like basket ball, 25.2% like throw ball.
Problem 2 :
In a class of 35 students, 7 students were absent on a particular day. What percentage of the students were absent?
Solution :
Total no. of students is 35.
No. of students absent is 7.
Percentage of students absent is
= (No. of students absent / total no. of students) ⋅ 100
= (7 / 35) ⋅ 100
= (1 / 5) ⋅ 100
= 20%
Hence, 20% of students were absent.
Problem 3 :
Ram bought 36 mangoes. 5 mangoes were rotten. What is the percentage of the mangoes that were rotten?
Solution :
Total number of mangoes is 36.
Number of rotten mangoes is 5.
Percentage of rotten mangoes is
= (5 / 36) ⋅ 100
= 13.89%
Hence, 13.89% of mangoes were rotten out of 36 mangoes.
Problem 4 :
In a class of 70, 60% are boys. Find the number of boys and girls.
Solution :
Percentage of boys in the class is 60.
Percentage of girls in the class is 40.
Total number of students is 70.
Number of boys in the class is
= 60% of 70
= 0.6 ⋅ 70
= 42
Number of girls in the class is
= 40% of 70
= 0.4 ⋅ 70
= 28
Hence, the number of boys in the class is 42 and the number of girls in the class is 28.
Problem 5 :
In 2010, the population of a town is 1,50,000. If it is increased by 10% in the next year, find the population in 2011.
Solution :
Population in 2010 is 150000.
If the population is increased by 10%, then the population after increment is
= 1.1 ⋅ 150000
= 165000
Hence, the population in 2011 is 1650000.
Problem 6 :
In a class of 50, 23 were girls and the rest were boys. What is the percentage of girls and the percentage of boys?
Solution :
Total no. of students in the class is 50.
No. of girls in the class is 23.
Percentage of girls is
= (No. of girls / Total no. of students) ⋅ 100
= (23 / 50) ⋅ 100
= 0.46 ⋅ 100
= 46%
Hence, 46% of students in the class are girls.
Problem 7 :
Adam got 66 marks out of 75 in Math and 72 out of 80 in Science. In which subject did he score more?
Solution :
To find in which subject he score good marks, we need to the percentage of marks he scored in each subjects.
Percentage of marks in math is
= (66 / 75) ⋅ 100
= 88%
percentage of marks in science is
= (72 / 80) ⋅ 100
= 90%
By comparing the percentage of marks scored in two subjects, Adam scored more marks in science.
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WORD PROBLEMS
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Word problems on quadratic equations
Area and perimeter word problems
Word problems on direct variation and inverse variation
Word problems on comparing rates
Converting customary units word problems
Converting metric units word problems
Word problems on simple interest
Word problems on compound interest
Word problems on types of angles
Complementary and supplementary angles word problems
Trigonometry word problems
Markup and markdown word problems
Word problems on mixed fractrions
One step equation word problems
Linear inequalities word problems
Ratio and proportion word problems
Word problems on sets and venn diagrams
Pythagorean theorem word problems
Percent of a number word problems
Word problems on constant speed
Word problems on average speed
Word problems on sum of the angles of a triangle is 180 degree
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Domain and range of rational functions with holes
Graphing rational functions with holes
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Translating the word problems in to algebraic expressions
Remainder when 2 power 256 is divided by 17
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Sum of all three digit numbers divisible by 6
Sum of all three digit numbers divisible by 7
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Sum of all three digit numbers formed using 1, 3, 4
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