PARALLEL LINES IN THE COORDINATE PLANE WORKSHEET

Problem 1 :

In the diagram given below, find the slope of each line. Determine whether the lines jand jare parallel.

Problem 2 :

In the diagram given below, find the slope of each line. Which lines are parallel?

Problem 3 :

Write an equation of the line through the point (2, 3) that has a slope 5.

Problem 4 :

In the diagram given below, line n1 has the equation

y = -x/3 -1 

Line n2 is parallel to the line n1 and passes through the point (3, 2).

Write the equation of the line n2.

1. Answer :

Line j1 has a slope of

m2 = 4/2

= 2

Line j2 has a slope of

m2 = 2/1

= 2

Since the slope of the lines jand jare equal, the lines jand jare parallel.

2. Answer :

Part 1 :

Find the slope of the line k1. Line k1 is passing through the points (0, 6) and (2, 0).

Let (x1, y1) = (0, 6) and (x2, y2) = (2, 0).

Slope (k1) = (y2 - y1)/(x2 - x1)

(0 - 6)/(2 - 0)

-6/2

- 3

Part 2 :

Find the slope of the line k2. Line k2 is passing through the points (-2, 6) and (0, 1).

Let (x1, y1) = (-2, 6) and (x2, y2) = (0, 1).

Slope (k2) = (y2 - y1)/(x2 - x1)

(1 - 6)/[0 -(-2)]

 = (1 - 6)/[0 + 2]

-5/2

Part 3 :

Find the slope of the line k3. Line k3 is passing through the points (-6, 5) and (-4, 0).

Let (x1, y1) = (-6, 5) and (x2, y2) = (-4, 0).

Slope (k3) = (y2 - y1)/(x2 - x1)

(0 - 5)/[-4 - (-6)]

-5/(-4 + 6)

-5/2

Compare the slopes. Because k2 and k3 have the same slope, they are parallel. Line k1 has a different slope, so it is not parallel to either of the lines.

3. Answer :

Slope-intercept form equation of a line :

y = mx + b ----(1) 

Substitute (x, y) = (2, 3) and m = 5.

3 = 5(2) + b

Simplify.

3 = 10 + b

Subtract 3 from both sides.

-7 = b

The equation of the required line is

(1)----> y = 5x - 7

4. Answer :

The slope of the line n1 is -1/3. Because the lines n1 and n2 are parallel, they have the same slope. So, the slope of the line n2 is also -1/3.

Slope-intercept form equation of a line :

y = mx + b ----(1) 

Because the line n2 is passing through (3, 2), substitute

(x, y) = (3, 2) and m = -1/3

2 = (-1/3)(3) + b

Simplify.

2 = -1 + b

Add 1 to both sides.

3 = b

The equation of the required line is

(1)----> y = (-1/3)x + 3

y = -x/3 + 3

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