In this page mixed word problem6 you can find the question as well as
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see every problems with detailed solution and explanation.**Question:**

In three packets there were $ 13 ⅔ ,$ 25
⅓ and $ 30
⅙. The total amount in all the four packets is $ 95. What is the amount in the fourth packet?

Basic idea:

Here we have 3 amounts.But we have the sum of four amounts that is $95.Now we need to find the fourth amount.To solve this problem we have to add all the three amounts and we have to subtract this from $95.

Sum of amount <br> of three packets = 13 ⅔ + 25
⅓ + 30
⅙

Let "x" be the amount of fourth packet

Remaining amount of fourth packet = 95 - (13 ⅔ + 25
⅓ + 30
⅙)

= 95 - [(39+2)/3 + (75+1)/3 + (180+1)/6

= 95 - [ 41/3 +76/3 + 181/6]

= 95 - [(41/3) x (2/2) + (76/3)x(2/2) + 181/6]

= 95 - [(82/6 + 152/6 +181/6)]

= 95 - [ (82+152+181)/6]

= 95 - [415/6]

= 95/1 - 415/6

= (95/1) x (6/6) - 415/6

= (570/6) - (415/6)

= (570-415)/6

= 155/6

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