Question 1 :
What is the mean absolute deviation for the following numbers?
5, 8, 10, 10, 12, 9
Question 2 :
The data represent the height, in feet, of various buildings. Find the mean absolute deviation.
60, 58, 54, 56, 63, 65, 62, 59, 56, 57
Question 3 :
What is the difference between a measure of center and a measure of variability ?
Question 1 :
What is the mean absolute deviation for the following numbers?
5, 8, 10, 10, 12, 9
Answer :
The mean is given by
= (5 + 8 + 10 + 10 + 12 + 9) / 6
= 54 / 6
= 9
Absolute deviations of observations from mean :
|5 - 9| = |-4| = 4
|8 - 9| = |-1| = 1
|10 - 9| = |1| = 1
|10 - 9| = |1| = 1
|12 - 9| = |3| = 3
|9 - 9| = |0| = 0
Calculate the mean absolute deviation by finding the mean of the above absolute deviations of observations from mean. Round to the nearest whole number.
Mean absolute deviation is
= (4 + 1 + 1 + 1 + 3 + 0) / 6
= 10 / 6
≈ 1.67
So, mean absolute deviation for the given data is about 1.67.
Question 2 :
The data represent the height, in feet, of various buildings. Find the mean absolute deviation.
60, 58, 54, 56, 63, 65, 62, 59, 56, 57
Answer :
The mean is given by
= (60 + 58 + 54 + 56 + 63 + 65 + 62 + 59 + 56 + 57) / 10
= 590 / 10
= 59
Absolute deviations of observations from mean :
|60 - 59| = |1| = 1
|58 - 59| = |-1| = 1
|54 - 59| = |-5| = 5
|56 - 59| = |-3| = 3
|63 - 59| = |4| = 4
|65 - 59| = |6| = 6
|62 - 59| = |3| = 3
|59 - 59| = |0| = 0
|56 - 59| = |-3| = 3
|57 - 59| = |-2| = 2
Calculate the mean absolute deviation by finding the mean of the above absolute deviations of observations from mean. Round to the nearest whole number.
Mean absolute deviation is
= (1 + 1 + 5 + 3 + 4 + 6 + 3 + 0 + 3 + 2) / 10
= 28 / 10
= 2.8
≈ 3
Question 3 :
What is the difference between a measure of center and a measure of variability ?
Answer :
A measure of center is a number that indicates where the “middle” or center of a data set is, while a measure of variability is a number that indicates how much the data are spread out from the center of the data.
Kindly mail your feedback to v4formath@gmail.com
We always appreciate your feedback.
©All rights reserved. onlinemath4all.com
Jun 20, 25 08:15 PM
Jun 20, 25 07:44 PM
Jun 19, 25 08:35 PM