# MATH GAMES

Game 1 :

Your dad says that you can play video game, if you solve 10 math problems in 50 minutes. Find themaximum time that you can take to solve each problem.

Game 2 :

I am a two-dgit number, i am not a prime number and i am divisible by both 4 and 7. If my value is between 20 and 30, who am i?

Game 3 :

When 5 times a number y is divided by 8, the result is 15. What is the value of y?

Game 4 :

I am a number. If 17 is taken away from me, i will become 13. Who am i?

Game 5 :

You and your friend are playing a game. You score x points and your friend scores 14 less than two times of the points you score. If both of you score 31 points together. who is the winner?

Game 6 :

In jar A, there were some jelly beans. After 7 jellyy beans are transferred to Jar B, two jars have the same number of jelly beans. If there were 5 Jelly beans initially in Jar B, find the number of Jelly beans in Jar A initially.

Game 7 :

The sum of the digits in a two digit number is 11. If the number is divisible by 4, guess the number.

Game 8 :

Three persons Mr. John, Mr. Henry and Mr. Peter together have \$51. Mr. John has \$4 less than Mr. Henry and Mr. Peter has got \$5 less than Mr. Henry. Find the amount of money each one has.

Game 9 :

Your friend says that he will allow you to play his video game, if you can solve the following math puzzle.

"If the sum of two numbers is 52 and their difference is 2, find the two numbers."

Game 10 :

One student is asked to divide a half of a number by 6 and other half by 4 and then to add the two quantities. Instead of doing so the student divides the given number by 5. If the answer is 4 short of the correct answer then find the number. Maximum time taken to solve each problem :

⁵⁰⁄₁₀

= 5 minutes

28 is the number between 20 and 30, which is also divisible by both 4 and 7.

⁵ʸ⁄₈ = 15

5y = 120

y = 24

Let x be the number.

x - 17 = 13

x = 30

Therefore, the number is 30.

Your friend's score = 2x - 14

Given : Total points scored by you and your friens is 31.

x + (2x - 14) = 31

x + 2x - 14 = 31

3x - 14 = 31

3x = 45

x = 15

Your friend's score = 2(15) - 14 = 16

Let x be the number of jelly beans initially in jar A.

It is given that there were 5 jelly beans initially in Jar B. If 7 jellyy beans are transferred from jar A to jar B,

number of jelly beans in jar A = x - 5

number of jelly beans in jar B = 12

Given : After 7 jellyy beans are transferred to Jar B, two jars have the same number of jelly beans.

x - 5 = 12

x = 17

There were 17 jelly beans initially in jar A.

We can guess some two-digit numbers such that the sum of the digits is 11.

29, 38, 47, 56, 65, 74, 83, 92

Among those numbers, 56 and 92 are divisible  by 4. So, the two-digit number can be 56 or 92.

Let j, h and p be the amounts of money had by Mr. John, Mr. Henry and Mr. Peter respectively.

j + h + p = 51 ----(1)

j = h - 4 ----(2)

p = h - 5 ----(3)

Substitute j = h - 4 and p = h - 5 into (1).

(h - 4) + h + (h - 5) = 51

h - 4 + h + h - 5 = 51

3h - 9 = 51

3h = 60

h = 20

Substitute h = 20 into (2) and (3).

 j = 20 - 4j = 16 p = 20 - 5p = 15

Therefore, Mr. John has \$16, Mr Henry has \$20 and Mr. Peter has \$15.

Let x and y be the two numbers.

x + y = 52 ----(1)

x - y = 2 ----(2)

(1) + (2) :

2x = 54

x = 27

Substitute x = 27 into (1).

27 + y = 52

y = 25

Therefore, the two numbers are 25 and 27.

Let x be the required.

Given : The student is asked to divide a half of the number by 6 and other half by 4 and then to add the two quantities.

= [(ˣ⁄₂) ÷ 6] + [(ˣ⁄₂) ÷ 4]

= ˣ⁄₁₂ + ˣ⁄₈ ----(1)

Given : Insrtead of doing the above work, the student divides the given number by 5.

ˣ⁄₅ ----(2)

From the given information, the result in (2) is 4 short of the result in (1).

(1) = (2) + 4

ˣ⁄₁₂ + ˣ⁄₈ ˣ⁄₅ + 4

The least common multiple of the denominators (12, 8, 5) is 120.

Multiply both sides of the equation above by 120 to get rid of the denominators.

120(ˣ⁄₁₂ + ˣ⁄₈) = 120(ˣ⁄₅ + 4)

120(ˣ⁄₁₂) + 120(ˣ⁄₈) = 120(ˣ⁄₅+ 120(4)

10x + 15x = 24x + 480

25x = 24x + 480

x = 480

Therefore, the number is 480.

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