**Math Arithmetic Problems With Solutions :**

Here you can see some arithmetic problems. We have prepared these questions, inorder to help the students who are trying to get better score in competitive exams.

To find question 1 to 7, please visit "Arithmetic Problems With Solutions for Competitive Exams"

**Question 8 :**

Which of the following is a multiple of 10 ?

**Solution :**

Multiples of 10 ends with with 0.

Options B ends with 0, So 10,030 is a multiple of 10.

**Question 9 :**

Which of the following is a multiple of 5 and 2 ?

(A) 2, 203 (B) 2, 342 (C) 1, 005 (D) 7, 790 (E) 9, 821

**Solution :**

Multiple of 2 ends with one of the following numbers 0, 2, 4, 6 or 8.

Multiple of 5 ends with 5 or 0.

From the given numbers 7790 satisfies the above conditions. So 7790 is a multiple of 5 and 2.

**Question 10 : **

Which of the following is a multiple of both 3 and 10 ?

(A) 103 (B) 130 (C) 210 (D) 310 (E) 460

**Solution :**

In order to find which of the following number is a multiple of both 3 and 10, let us use divisibility test.

If the sum of the digits is a multiple of 3, then the given number is divisible by 3.

If the number ends with 0, then it is divisible by 10.

From the given options , option C satisfies both the conditions.

2 + 1 + 0 = 21 (divisible by 3 and ends with 0)

Hence 210 is divisible by both 3 and 10.

**Question 11 :**

Which of the following is a multiple of 2, 3 and 5 ?

(A) 165 (B) 235 (C) 350 (D) 420 (E) 532

**Solution :**

165 ==> 1 + 6 + 5 = 12 (divisible by 3), it is not even.

235 ==> 2 + 3 + 5 = 10 (not divisible by 3)

350 ==> 3 + 5 + 0 = 8 (not divisible by 3)

420 ==> 4 + 2 + 0 = 6(divisible by 3, ends with 0)

Hence 420 is divisible by 2, 3 and 5.

**Question 12 :**

Which of the following is an even multiple of both 3 and 5 ?

(A) 135 (B) 155 (C) 250 (D) 350 (E) 390

**Solution :**

390 ==> 3 + 9 + 0 = 12 (divisible by 3)

It ends with 0. So it is divisible by 5.

**Question 13 :**

Professor Jones bought a large carton of books. she gave 3 books to each student in her class and there were no books left over. Which of the following could be the number of books she distributed ?

(A) 133 (B) 143 (C) 525 (D) 271 (E) 332

**Solution :**

If the required number of books is the multiple of 3, we will not have any book left over.

525 ==> 5 + 2 + 5 = 12 (divisible by 3)

Hence 525 books could be distributed.

After having gone through the stuff given above, we hope that the students would have understood, "Math Arithmetic Problems With Solutions".

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