MATH ARITHMETIC PROBLEMS WITH SOLUTIONS

About "Math Arithmetic Problems With Solutions"

Math Arithmetic Problems With Solutions :

Here you can see some arithmetic problems. We have prepared these questions, inorder to help the students who are trying to get better score in competitive exams.

Math Arithmetic Problems With Solutions

To find question 1 to 7, please visit  "Arithmetic Problems With Solutions for Competitive Exams"

Question 8 :

Which of the following is a multiple of 10 ?

Solution :

Multiples of 10 ends with with 0.

Options B ends with 0, So 10,030 is a multiple of 10.

Question 9 :

Which of the following is a multiple of 5 and 2 ?

(A)  2, 203  (B)  2, 342  (C)  1, 005  (D)  7, 790  (E)  9, 821

Solution :

Multiple of 2 ends with one of the following numbers 0, 2, 4, 6 or 8.

Multiple of 5 ends with 5 or 0.

From the given numbers 7790 satisfies the above conditions. So 7790 is a multiple of 5 and 2.

Question 10 :

Which of the following is a multiple of both 3 and 10 ?

(A)  103  (B)  130  (C)  210  (D)  310  (E)  460

Solution :

In order to find which of the following number is a multiple of both 3 and 10, let us use divisibility test.

Divisibility rule of 3 :

If the sum of the digits is a multiple of 3, then the given number is divisible by 3. 

Divisibility rule of 10 :

If the number ends with 0, then it is divisible by 10.

From the given options , option C satisfies both the conditions.

2 + 1 + 0  =  21 (divisible by 3 and ends with 0)

Hence 210 is divisible by both 3 and 10.

Question 11 :

Which of the following is a multiple of 2, 3 and 5 ?

(A)  165  (B)  235  (C)  350  (D)  420  (E)  532

Solution :

165  ==> 1 + 6 + 5  =  12 (divisible by 3), it is not even.

235  ==>  2 + 3 + 5 =  10 (not divisible by 3)

350  ==>  3 + 5 + 0  =  8 (not divisible by 3)

420  ==>  4 + 2 + 0  =  6(divisible by 3, ends with 0)

Hence 420 is divisible by 2, 3 and 5.

Question 12 :

Which of the following is an even multiple of both 3 and 5 ?

(A)  135  (B)  155  (C)  250  (D)  350  (E)  390

Solution :

390  ==> 3 + 9 + 0  =  12 (divisible by 3)

It ends with 0. So it is divisible by 5.

Question 13 :

Professor Jones bought a large carton of books. she gave 3 books to each student in her class and there were no books left over. Which of the following could be the number of books she distributed ?

(A)  133  (B)  143  (C)  525  (D)  271  (E)  332

Solution :

If the required number of books is the multiple of 3, we will not have any book left over.

525  ==>  5 + 2 + 5  =  12 (divisible by 3)

Hence 525 books could be distributed.

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