INEQUALITIES IN ONE TRIANGLE WORKSHEET

Problem 1 :

Write the sides of the triangle shown below in order from least to greatest.

Problem 2 :

Write the angles of the triangle shown below in order from smallest to largest.

Problem 3 :

In the triangle shown below AB ≅ AC and BC > AB. What can we conclude about the angles in triangle ABC?

Problem 4 :

Construct a triangle with the given group of side lengths, if possible.

2 cm, 2 cm, 5 cm

Problem 5 :

Construct a triangle with the given group of side lengths, if possible.

3 cm, 2 cm, 5 cm

Problem 6 :

Construct a triangle with the given group of side lengths, if possible.

4 cm, 2 cm, 5 cm

Answers

1. Answer :

In the triangle GHJ above, we have

m∠G < m∠H < m∠J

So, the smallest angle is m∠G and the largest angle m∠J.

In any triangle, the smallest angle is always across from the shortest side and the largest angle is always across from the longest side.

Hence, the order of sides of the triangle from least to greatest is

JH < JG < GH

2. Answer :

In the triangle PQR above, we have

PQ < PR < QR

So, the shortest side is PQ and the longest side is QR.

In any triangle, the smallest angle is always across from the shortest side and the largest angle is always across from the longest side.

Hence, the order of angles of the triangle from smallest to largest is

m∠R < m∠Q < m∠P

3. Answer :

Because AB ≅ AC, triangle ABC is isosceles.

So, we have

m∠B ≅ m∠C

Therefore, m∠B = m∠C.

Because BC > AB, m∠A > m∠C by Theorem 1.

By substitution, m∠A > m∠B.

In addition, you can conclude that m∠A > 60°. m∠B < 60° and m∠C < 60°.

4. Answer :

2 cm, 2 cm, 5 cm

We can not construct a triangle with the given side lengths.

Because, sum of the lengths of any two sides of a triangle must be greater than the third side by Theorem 4.

In the given side lengths, we have

2 + 2 < 5

(Does not satisfy the theorem)

The diagram given below illustrates that a triangle can not be constructed with the given side lengths.

5. Answer :

3 cm, 2 cm, 5 cm

We can not construct a triangle with the given side lengths.

Because, sum of the lengths of any two sides of a triangle must be greater than the third side by Theorem 4.

In the given side lengths, we have

3 + 2  =  5

(Does not satisfy the theorem)

The diagram given below illustrates that a triangle can not be constructed with the given side lengths.

6. Answer :

4 cm, 2 cm, 5 cm

In the given side lengths, we have

4 + 2 > 5

4 + 5 > 2

2 + 5 > 4

In the given side lengths, it is clear that the sum of any two sides is greater than the third side.

Because the given side lengths satisfy Theorem 4, we can construct a triangle with the given side lengths.

Kindly mail your feedback to v4formath@gmail.com

We always appreciate your feedback.

©All rights reserved. onlinemath4all.com

Recent Articles

  1. Quadratic Equation Word Problems Worksheet with Answers

    Oct 07, 22 12:25 PM

    Quadratic Equation Word Problems Worksheet with Answers

    Read More

  2. Problems on Quadratic Equations

    Oct 07, 22 12:20 PM

    Problems on Quadratic Equations

    Read More

  3. SAT Math Practice Worksheets

    Oct 07, 22 09:38 AM

    SAT Math Practice Worksheets - Topic wise worksheet with step by step explanation for each question

    Read More