Subscribe to our βΆοΈ YouTube channel π΄ for the latest videos, updates, and tips.
To write a decimal in expanded form, we have to break down down each digit according to its place value. We can start with the whole number portion, identifying the ten thusands, thousands, hundreds, tens, ones places. Then, move on to the tenths, hundredths, and thousandths and ten thousandths places.

Write the following decimals in expanded form :
Example 1 :
23.87
Solution :
= 23.87
Multiply each digit of 23.87 by its corresponding place value.
= 2x10 + 3x1 + 8xΒΉβββ + 7xΒΉββββ
= 20 + 3 + βΈβββ + β·ββββ
= 20 + 3 + 0.8 + 0.07
Example 2 :
7.8
Solution :
= 7.8
= 7x1 + 8xΒΉβββ
= 7 + βΈβββ
= 7 + 0.8
Example 3 :
5.206
Solution :
= 5.206
= 5x1 + 2xΒΉβββ + 0xΒΉββββ + 6xΒΉβββββ
= 5 + Β²βββ + 0 + βΆβββββ
= 5 + 0.2 + 0.006
Example 4 :
1025.3
Solution :
= 1025.3
= 1x1000 + 0x100 + 2x10 + 5x1 + 3xΒΉβββ
= 1000 + 0 + 20 + 5 + Β³βββ
= 1000 + 0 + 20 + 5 + 0.3
Example 5 :
5.36
Solution :
= 5.36
= 5x1 + 3xΒΉβββ + 6xΒΉββββ
= 5 + Β³βββ + βΆββββ
= 5 + 0.3 + 0.06
Example 6 :
0.389
Solution :
= 0.389
= 3xΒΉβββ + 8xΒΉββββ + 9xΒΉβββββ
= Β³βββ + βΈββββ + βΉβββββ
= 0.3 + 0.08 + 0.009
Example 7 :
0.0746
Solution :
= 0.0746
= 7xΒΉββββ + 4xΒΉβββββ + 6xΒΉββββββ
= β·ββββ + β΄βββββ + βΆββββββ
= 0.07 + 0.004 + 0.0006
Example 8 :
0.000043
Solution :
= 0.000043
= 4xΒΉβββββββ + 3xΒΉββββββββ
= β΄βββββββ + Β³ββββββββ
= 0.00004 + 0.000003
Example 9 :
2.4358 x 102
Solution :
= 2.4358 x 102
= 243.58
= 2x100 + 4x10 + 3x1 + 5xΒΉβββ + 8xΒΉββββ
= 200 + 40 + 3 + β΅βββ + βΈββββ
= 200 + 40 + 3 + 0.5 + 0.08
Example 10 :
9.57 x 10-4
Solution :
= 9.57 x 10-4
= 0.000957
= 9xΒΉββββββ + 5xΒΉβββββββ + 7xΒΉββββββββ
= βΉββββββ + β΅βββββββ + β·ββββββββ
= 0.0009 + 0.00005 + 0.000007
Example 11 :
(1.78 x 102) x (2.54 x 101)
Solution :
= (1.78 x 102) x (2.54 x 101)
= (1.78 x 2.54) x (102 x 101)
= 4.5212 x 102 + 1
= 4.5212 x 103
= 4521.2
= 4x1000 + 5x100 + 2x10 + 1x1 + 2xΒΉβββ
= 4000 + 500 + 20 + 1 + Β²βββ
= 4000 + 500 + 20 + 0.2
Example 12 :
(2.9375 x 10-2) Γ· (1.25 x 101)
Solution :
= (2.9375 x 10-2) Γ· (1.25 x 101)
= (2.9375 Γ· 1.25) x (10-2 Γ· 101)
= 2.35 x 10-2-1
= 2.35 x 10-3
= 0.00235
= 2xΒΉβββββ + 3xΒΉββββββ + 5xΒΉβββββββ
= Β²βββββ + Β³ββββββ + β΅βββββββ
= 0.002 + 0.0003 + 0.00005
Example 13 :
(1.5 x 10-2) + (2.3 x 10-2)
Solution :
= (1.5 x 10-2) + (2.3 x 10-2)
Factor 10-2.
= (1.5 + 2.3) x 10-2
= 3.8 x 10-2
= 0.038
= 3xΒΉββββ + 8xΒΉβββββ
= Β³ββββ + βΈβββββ
= 0.03 + 0.008
Example 14 :
(2.9 x 10-3) + (5.6 x 10-1)
Solution :
= (2.9 x 10-3) + (5.6 x 10-2)
= (2.9 x 10-3) + (56.0 x 10-3)
Factor 10-3.
= (2.9 + 56.0) x 10-3
= 58.9 x 10-3
= 0.0589
= 5xΒΉββββ + 8xΒΉβββββ + 9xΒΉββββββ
= β΅ββββ + βΈβββββ + βΉββββββ
= 0.05 + 0.008 + 0.0009
Example 15 :
(8.4 x 10-3) - (1.6 x 10-3)
Solution :
= (8.4 x 10-3) - (1.6 x 10-3)
Factor 10-3.
= (8.4 - 1.6) x 10-3
= 6.8 x 10-3
= 0.0068
= 6xΒΉβββββ + 8xΒΉββββββ
= βΆβββββ + βΈββββββ
= 0.006 + 0.0008
Subscribe to our βΆοΈ YouTube channel π΄ for the latest videos, updates, and tips.
Kindly mail your feedback to v4formath@gmail.com
We always appreciate your feedback.
About Us | Contact Us | Privacy Policy
Β©All rights reserved. onlinemath4all.com
Dec 14, 25 06:42 AM
Dec 14, 25 06:38 AM
Dec 13, 25 10:11 AM