Here we are going to see how to prove the given Points are collinear.
To prove the the given three points are colinear, we may use the following methods.
(i) Using slope
(ii) Equation of the line
(iii) Using the formula for area of triangle
(iv) Using determinant
Example
Show that the points (1, 3), (2, 1) and (1/2, 4) are collinear, by using (i) concept of slope (ii) using a straight line and (iii) any other method
Solution :
Let the points be A (1, 3) B (2, 1) and C (1/2, 4)
If the given points are collinear, then
Slope of AB = Slope of BC
Slope of a line :
m = (y_{2} - y_{1})/(x_{2} - x_{1})
Slope of AB : m = (1-3)/(2-1) m = -2 ------(1) |
Slope of BC : m = (4-1)/((1/2)-2) m = 3/(-3/2) m = -2 ------(2) |
Hence the given points are collinear.
(ii) using a straight line
If the equations formed using any two points on the line will be equal, then we may decide that the given points are collinear.
A (1, 3) B (2, 1)
Equation of AB :
(y−y_{1})/(y_{2}−y_{1}) = (x−x_{1})/(x_{2}-x_{1})
(y - 3)/(1 - 3) = (x - 1)/(2 - 1)
(y - 3)/(-2) = (x - 1)/1
y - 3 = -2 (x - 1)
y - 3 = -2x + 2
y = -2x + 2 + 3
y = -2x + 5
Equation of BC :
B (2, 1) and C (1/2, 4)
(y−y_{1})/(y_{2}−y_{1}) = (x−x_{1})/(x_{2}-x_{1})
(y - 1)/(4 - 1) = (x - 2)/((1/2) - 2)
(y - 1)/3 = (x - 2)/(-3/2)
y - 1 = -2 (x - 2)
y - 1 = -2x + 4
y = -2x + 4 + 1
y = - 2x + 5
Hence the given points are colinear.
(iii) any other method
= (1/2) [(1 + 8 + 3/2) - (6 + 1/2 + 4)]
= (1/2) [(9 + 3/2) - (10 + 1/2)]
= (1/2) [(21/2) - (21/2)]
= (1/2) [0]
= 0
Hence the given points are collinear.
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