Subscribe to our ▶️ YouTube channel 🔴 for the latest videos, updates, and tips.
In this section, we are going you to see how to graph a circle on the xy-plane when its equation is given. To graph a circle on the xy-plane, we need to know its center and radius. So, we have to find the center and radius from the equation of the circle given.
Equation of a circle in standard form with center (0, 0) :
x2 + y2 = r2
Equation of a circle in standard form with center (h, k) :
(x - h)2 + (y - k)2 = r2
Equation of a circle in general form :
x2 + y2 + 2gx + 2fy + c = 0
center = (-g, -f)
radius = √(g2 + f2 - c)
Graph the circles whose equations are given :
Example 1 :
x2 + y2 = 16
Solution :
The the given equation is in the form of
x2 + y2 = r2.
Center of the circle is (0, 0).
r2 = 16
r = √16
radius = 4 units

Example 2 :
(x - 2)2 + (y + 3)2 = 16
Solution :
The the given equation of the circle is in the form of
(x - h)2 + (y - k)2 = r2 ----(1)
Center of the circle is (h, k) and radius is r.
(x - 2)2 + (y + 3)2 = 16
(x - 2)2 + (y - (-3))2 = 42 ----(2)
Comparing (1) and (2),
center (h, k) = (2, -3)
r2 = 42
r = 4
radius = 4 units

Example 3 :
x2 + y2 - 2x - 6y + 1 = 0
Solution :
The equation of the given circle is in general form
x2 + y2+ 2gx + 2fy + c = 0 ----(1)
center = (-g, -f)
radius = √(g2 + f2 - c)
x2 + y2 - 2x - 6y + 1 = 0 ----(2)
Comparing (1) and (2),
2g = -2 ----> g = -1 ----> -g = 1
2f = -6 ----> f = -3 ----> -f = 3
center (-g, -f) = (1, 3)
radius = √(g2 + f2 - c)
= √(12 + 32 - 1)
= √(1 + 9 - 1)
= √9
r = 3 units

Example 4 :
Give the equation of the circle whose center is (4, - 3) and goes through (1, 5).
Solution :
Center is (4, -3) and passes through the point (1, 5)
Distance between the points (4, -3) and (1, 5).
Radius = distance between center and one of the points of the circle.
= √(x2 - x1)2 + (y2 - y1)2
= √(4 - 1)2 + (-3 - 5)2
= √32 + (-8)2
= √(9 + 64)
= √73
Equation of circle :
(x - h)2 + (y - k)2 = r2
(x - 4)2 + (y - (-3))2 = √732
(x - 4)2 + (y + 3)2 = 73
x2 - 8x + 16 + y2 + 6y + 9 = 73
x2 + y2 - 8x + 6y + 16 + 9 - 73 = 0
x2 + y2 - 8x + 6y - 48 = 0
Question 5 :
Give the equation of circle whose endpoints of a diameter at (4, -1) and (4, -5)
Solution :
Endpoint of the diameter (4, -1) and (4, -5)
= (x1 + x2)/2, (y1 + y2)/2
= (4 + 4)/2, (-1 - 5)/2
= 8/2, -6/2
= (4, -3)
Center of the circle is (4, -3).
Radius = distance between center and one of the points of the circle.
= √(x2 - x1)2 + (y2 - y1)2
= √(4 - 4)2 + (-3 - (-1))2
= √02 + (-3 + 1)2
= √(-2)2
= √4
= 2
Equation of circle :
(x - h)2 + (y - k)2 = r2
(x - 4)2 + (y - (-3))2 = 22
(x - 4)2 + (y + 3)2 = 22
x2 - 2x(4) + 42 + y2 + 2y(3) + 32 = 4
x2 - 8x + y2 + 6y + 16 + 9 = 4
x2 + y2 - 8x + 6y + 25 - 4 = 0
x2 + y2 - 8x + 6y + 21 = 0
Question 6 :
Graph the circles
a) (x - 3)2 + (y + 1)2 = 4
b) (x - 2)2 + (y - 5)2 = 9
c) (y + 4)2 + (x + 2)2 = 4
Solution :
a) (x - 3)2 + (y + 1)2 = 4
(x - 3)2 + (y - (-1))2 = 22
Comparing with (x - h)2 + (y - k)2 = r2
Here center (h, k) is (-3, -1) and radius = 2

b) (x - 2)2 + (y - 5)2 = 9
(x - 2)2 + (y - 5)2 = 32
Comparing with (x - h)2 + (y - k)2 = r2
Here center (h, k) is (2, 5) and radius = 3

c) (y + 4)2 + (x + 2)2 = 4
(y + 4)2 + (x + 2)2 = 4
(x + 2)2 + (y + 4)2 = 4
(x - (-2))2 + (y - (-4))2 = 22
Comparing with (x - h)2 + (y - k)2 = r2
Here center (h, k) is (-2, -4) and radius = 2
Question 7 :
A circle has equation x2 + y2 = 100.
(a) Write down the co-ordinates of the centre of the circle.
(b) Write down the radius of the circle.
Solution :
x2 + y2 = 100
x2 + y2 = 102
Center of the circle is (0, 0) and radius of the circle is 10.
Subscribe to our ▶️ YouTube channel 🔴 for the latest videos, updates, and tips.
Kindly mail your feedback to v4formath@gmail.com
We always appreciate your feedback.
About Us | Contact Us | Privacy Policy
©All rights reserved. onlinemath4all.com
Dec 14, 25 06:42 AM
Dec 14, 25 06:38 AM
Dec 13, 25 10:11 AM