HOW TO GRAPH CIRCLES

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In this section, we are going you to see how to graph a circle on the xy-plane when its equation is given. To graph a circle on the xy-plane, we need to know its center and radius. So, we have to find the center and radius from the equation of the circle given. 

Equation of a circle in standard form with center (0, 0) :

x2 + y2  = r2

Equation of a circle in standard form with center (h, k) :

(x - h)2 + (y - k)2  = r2

Equation of a circle in general form :

x2 + y2 + 2gx + 2fy + c = 0

center = (-g, -f)

radius = √(g2 + f2 - c)

Graph the circles whose equations are given :

Example 1 :

x+ y2 = 16

Solution :

The the given equation is in the form of

x2 + y2 = r2.

Center of the circle is (0, 0). 

r2 = 16

r = √16

radius = 4 units

Example 2 :

(x - 2)+ (y + 3)2 = 16

Solution :

The the given equation of the circle is in the form of

(x - h)+ (y - k)2 = r2 ----(1)

Center of the circle is (h, k) and radius is r.

(x - 2)+ (y + 3)2 = 16

(x - 2)+ (y - (-3))2 = 4----(2)

Comparing (1) and (2),

center (h, k) = (2, -3)

r2 = 42

r = 4

radius = 4 units

Example 3 :

x+ y2 - 2x - 6y + 1 = 0

Solution :

The equation of the  given circle is in general form

x+ y2+ 2gx + 2fy + c = 0 ----(1)

center = (-g, -f)

radius = √(g2 + f2 - c)

x+ y2 - 2x - 6y + 1 = 0 ----(2)

Comparing (1) and (2),

2g = -2 ----> g = -1 ----> -g = 1

2f = -6 ----> f = -3 ----> -f = 3

center (-g, -f) = (1, 3)

radius = √(g2 + f2 - c)

= √(12 + 32 - 1)

= √(1 + 9 - 1)

= √9

r = 3 units

Example 4 :

Give the equation of the circle whose center is (4, - 3) and goes through (1, 5).

Solution :

Center is (4, -3) and passes through the point (1, 5)

Distance between the points (4, -3) and (1, 5).

Radius = distance between center and one of the points of the circle.

= √(x2 - x1)2 + (y2 - y1)2

= √(4 - 1)2 + (-3 - 5)2

= √32 + (-8)2

= √(9 + 64)

= √73

Equation of circle :

(x - h)+ (y - k)2 = r2

(x - 4)+ (y - (-3))2 = √732

(x - 4)+ (y + 3)2 = 73

x2 - 8x + 16 + y+ 6y + 9 = 73

x2 + y- 8x + 6y + 16 + 9 - 73 = 0

x2 + y- 8x + 6y - 48 = 0

Question 5 :

Give the equation of circle whose endpoints of a diameter at (4, -1) and (4, -5)

Solution :

Endpoint of the diameter (4, -1) and (4, -5)

= (x1 + x2)/2, (y1 + y2)/2

= (4 + 4)/2, (-1 - 5)/2

= 8/2, -6/2

= (4, -3)

Center of the circle is (4, -3).

Radius = distance between center and one of the points of the circle.

= √(x2 - x1)2 + (y2 - y1)2

= √(4 - 4)2 + (-3 - (-1))2

= √02 + (-3 + 1)2

= √(-2)2

= √4

= 2

Equation of circle :

(x - h)+ (y - k)2 = r2

(x - 4)+ (y - (-3))2 = 22

(x - 4)+ (y + 3)2 = 22

x2 - 2x(4) + 4+ y2 + 2y(3) + 32 = 4

x2 - 8x + y2 + 6y + 16 + 9 = 4

x2 + y2 - 8x + 6y + 25 - 4 = 0

x2 + y2 - 8x + 6y + 21 = 0

Question 6 :

Graph the circles 

a) (x - 3)+ (y + 1)2 = 4

b)  (x - 2)+ (y - 5)2 = 9

c)  (y + 4)+ (x + 2)2 = 4

Solution :

a) (x - 3)+ (y + 1)2 = 4

(x - 3)+ (y - (-1))2 = 22

Comparing with (x - h)+ (y - k)2 = r2

Here center (h, k) is (-3, -1) and radius = 2

graphing-circle-q1

b)  (x - 2)+ (y - 5)2 = 9

(x - 2)+ (y - 5)2 = 32

Comparing with (x - h)+ (y - k)2 = r2

Here center (h, k) is (2, 5) and radius = 3

graphing-circle-q2.png

c)  (y + 4)+ (x + 2)2 = 4

(y + 4)+ (x + 2)2 = 4

 (x + 2)2 + (y + 4)= 4

 (x - (-2))2 + (y - (-4))= 22

Comparing with (x - h)+ (y - k)2 = r2

Here center (h, k) is (-2, -4) and radius = 2

Question 7 :

A circle has equation x2 + y2 = 100.

(a) Write down the co-ordinates of the centre of the circle.

(b) Write down the radius of the circle.

Solution :

x2 + y2 = 100

x2 + y2 = 102

Center of the circle is (0, 0) and radius of the circle is 10.

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