# HOW TO FIND WHETHER THE PARABOLA INTERSECTS X AXIS WITHOUT GRAPH

## About "How to find whether the parabola intersects x axis without graph"

How to find whether the parabola intersects x axis without graph :

Here we are going to how to find whether the parabola intersects x axis without graphing.

We may find number of points where the parabola intersects the x-axis, using the formula for discriminant.

 Condition Number of intersecting points b2 − 4ac > 0b2 − 4ac = 0b2 − 4ac < 0 Intersects x-axis in two placesTouches x-axis at only one pointdoes not intersect x-axis

Let us look into some examples to understand the above concept.

Question 1 :

Without sketching the graphs, find whether the graphs of the following functions will intersect the x-axis and if so in how many points.

(i)   y = x2 + x + 2

Solution :

Discriminant  =  b2 − 4ac

a =  1, b = 1 and c = 2

b2 − 4ac  =  (1)2 − 4(1)(2)

=  1 - 8

=  -7 < 0

Does not intersect the x-axis.

(ii) y = x2 − 3x − 7

Solution :

Discriminant  =  b2 − 4ac

a =  1, b = -3 and c = -7

b2 − 4ac  =  (-3)2 − 4(1)(-7)

=  9 + 28

=  36 > 0

Hence the curve intersects x-axis at two points.

(iii) y = x2 + 6x + 9

Solution :

Discriminant  =  b2 − 4ac

a =  1, b = 6 and c = 9

b2 − 4ac  =  (6)2 − 4(1)(9)

=  36 - 36

=  0

Hence the curve does not intersect x-axis at any point.

Question 2 :

Write f(x) = x2 + 5x + 4 in completed square form.

Solution :

=   x2 + 5x + 4

Multiply and divide the coefficient of x by 2.

=   x2 + (2/2) ⋅ ⋅ x + 4

=   x2 + 2 ⋅ x ⋅ (5/2) + (5/2)2 - (5/2)2 + 4

=   (x + (5/2))2 - (25/4) + 4

=   (x + (5/2))2 + (16 - 25)/4

=   (x + (5/2))2 + (-9)/4

=   (x + (5/2))2 - (3/2)2

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