Let θ be the angle of inclination and m be the slope of the line.
Then, the relationship between the angle of inclination and slope of the line is given by
m = tanθ
Example 1 :
Find the slope of the line whose angle of inclination is 30°.
Solution :
The relationship between the angle of inclination θ and slope of the line m is given by
m = tanθ
Given : θ = 30°.
Then,
m = tan 30°
m = 1/√3
So, the slope of the line is 1/√3.
Example 2 :
Find the slope of the straight line whose angle of inclination is 60°.
Solution :
The relationship between the angle of inclination θ and slope of the line m is given by
m = tanθ
Given : θ = 60°.
Then,
m = tan 60°
m = √3
So, the slope of the line is √3.
Example 3 :
Find the slope of the straight line whose angle of inclination is 90°.
Solution :
The relationship between the angle of inclination θ and slope of the line m is given by
m = tanθ
Given : θ = 90°.
Then,
m = tan 90°
m = undefined
So, the slope of the line is undefined.
Example 4 :
Find the slope of the straight line whose angle of inclination is 45°.
Solution :
The relationship between the angle of inclination θ and slope of the line m is given by
m = tanθ
Given : θ = 45°.
Then,
m = tan 45°
m = 1
So, the slope of the line is 1.
Example 5 :
The side AB of a square ABCD is parallel to x-axis . Find the
(i) slope of AB
(ii) slope of BC
(iii) slope of the diagonal AC
Solution :
(i) Slope of AB :
Because the side AB is parallel to x-axis, angle formed by the side AB with x-axis is zero.
Then,
m = tan 0°
m = 0
So, the slope of the side AB is 0.
(ii) Slope of BC :
If the side AB is parallel to x-axis, then the side BC will be perpendicular to x-axis.
So, it forms the angle 90° with axis.
Then,
m = tan 90°
m = undefined
So, the slope of the side BC is undefined.
(ii) Slope of the diagonal AC :
Because AC is diagonal, the angle of inclination of the diagonal AC with x-axis is 45°.
Then,
m = tan 45°
m = 1
So, the slope of the diagonal AC is 1.
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