The formula to find the distance between the two points (x1, y1) and (x2, y2) is given by
d = √(x2 - x1)2 + (y2 - y1)2
Example 1 :
Find the distance between the following pairs of points :
(i) (2 , 3) (4 , 1)
Solution :
Distance between two points = √(x2 - x1)2 + (y2 - y1)2
Here x1 = 2, y1 = 3, x2 = 4 and y2 = 1
= √(4 - 2)2 + (1 - 3)2
= √2² + (-2)²
= √(4 + 4)
= √8
= 2 √2
(ii) (-5 , 7) (-1 , 3)
Solution :
Distance between two points = √(x2 - x1)2 + (y2 - y1)2
Here x1 = 5, y1 = 7, x2 = -1 and y2 = 3
= √(-1 -(-5))² + (3 - 7)²
= √(-1 + 5)² + (-4)²
= √4² + (-4)²
= √16 + 16
= √32
= 4 √2
(iii) (a , b) (-a , -b)
Solution :
Distance between two points = √(x2 - x1)2 + (y2 - y1)2
Here x1 = a, y1 = b, x2 = -a and y2 = -b
= √(-a -a)² + (-b - b)²
= √(-2a)² + (-2b)²
= √4a² + 4b²
= √4(a² + b²)
= √2 x 2(a² + b²)
= 2 √(a² + b²)
Example 2 :
Find the distance between the points (0, 0) and (36, 15).
Solution :
Let A (0,0) B (36,15)
Distance between two points = √(x2 - x1)2 + (y2 - y1)2
Here x1 = 0, y1 = 0, x2 = 36 and y2 = 15
= √(36 - 0)² + (15 - 0)²
= √(36)² + (15)²
= √1296 + 225
= √1521
= √39 x 39
= 39
So, the distance between the given towns A and B will be 39 km.
Example :
Determine if the points (1,5) (2,3) and (-2,-11) are collinear.
Solution :
A (1, 5) B(2, 3) and C (-2, -11)
Distance between A and B
Here x1 = 1, y1 = 5, x2 = 2 and y2 = 3
AB = √(2 - 1)² + (3 - 5)²
= √(1)² + (- 2)²
= √1 + 4
= √5
Distance between B and C
Here x1 = 2, y1 = 3, x2 = -2 and y2 = -11
BC = √(-2 - 2)2 + (-11 - 3)2
= √(-4)² + (-14)²
= √16 + 196
= √212
Distance between C and A
Here x1 = -2, y1 = -11, x2 = 1 and y2 = 5
CA = √(1 -(-2))² + (5 -(-11))²
= √(1+2)2 + (5 + 11)2
= √32 + 162
= √9 + 256
= √265
Since AB + BC ≠ CA
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