# HOW TO FIND LIMITS BY LOOKING AT A GRAPH

## Left hand limit

We say that the left-hand limit of f(x) as x approaches x0 (or the limit of f(x) as x approaches from the left) is equal to l1 if we can make the values of f(x) arbitrarily close to l1 by taking x to be sufficiently close to x0 and less than x0. It is symbolically written as

f(x0-)  =  lim x ->x0f(x)  =  l1

## Right hand limit

We say that the right-hand limit of f(x) as x approaches x0 (or the limit of f(x) as x approaches from the right) is equal to l2 if we can make the values of f(x) arbitrarily close to l2 by taking x to be sufficiently close to x0 and greater than x0. It is symbolically written as

f(x0+)  =  lim x ->x0f(x)  =  l2

From the above discussions we conclude that

lim x->x0 f(x)  =  L exists if the following hold :

(i) lim x->x0+ f(x) exists,

(ii)  lim x->x0- f(x) exists, and

(iii)  lim x->x0+ f(x)  =   lim x->x0- f(x)  =  L

When we get different values for f(x) as x0 approaches from left and from right, we may say that the function does not exist.

The picture given below will illustrate the concept.

There is no function to the left of x0. Hence the function is not defined.

Example 1 :

Use the graph to find the limits (if it exists). If the limit does not exist, explain why?

lim x->3 (4 - x)

Solution :

 f(x)  =  (4 - x)lim x->3- f(x)  =  4 - 3  =  1 f(x)  =  (4 - x)lim x->3+ f(x)  =  4 - 3  =  1

lim x->3 f(x)  =  4 - 3  =  1

lim x->3- f(x)  =  lim x->3+ f(x)  =  lim x->3 f(x)

The function is defined at x -> 3. Hence the required limit is 1.

Example 2 :

Use the graph to find the limits (if it exists). If the limit does not exist, explain why?

lim x->1 (x2 + 2)

Solution :

 f(x)  =  (x2 + 2)lim x->1- f(x)  =  12 + 2  =  3 f(x)  =  (x2 + 2)lim x->1+ f(x)  =  12 + 2  =  3

lim x->1 f(x)  =  x2 + 2  =  12 + 2  =  3

lim x->1- f(x)  =  lim x->1+ f(x)  =  lim x->1 f(x)

The function is defined at x -> 1. Hence the required limit is 3

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