Question 1 :
Find the first term and common difference of the arithmetic sequences whose nth terms are given below
(i) tn = -3 +2n
Solution :
To find the 1st term of the sequence, we have to apply n = 1.
1st term t1 = −3 + 2(1) t1 = −3 + 2 = -1 |
2nd term t2 = −3 + 2(2) t2 = −3 + 4 = 1 |
d = t2 - t1 = 1 - (-1) = 1 + 1 ==> d = 2
Hence the first term and common difference are -1 and 2 respectively.
(ii) tn = 4 - 7n
Solution :
To find the 1st term of the sequence, we have to apply n = 1.
1st term t1 = 4 - 7(1) t1 = 4 - 7 = -3 |
2nd term t2 = 4 - 7(2) t2 = 4 - 14 = -10 |
d = t2 - t1 = -10 - (-3) = -10 + 3 ==> d = -7
Hence the first term and common difference are -3 and -7 respectively.
Question 2 :
Find the 19th term of an A.P. -11,-15,-19,...
Solution :
nth term of the A.P
tn = a + (n - 1)d
a = -11 , d = -15 - (-11) = -15 + 11 ==> -4
t19 = -11 + (19 - 1)(-4)
= -11 + 18(-4)
= - 11 - 72
t19 = -83
Question 3 :
Which term of an A.P. 16, 11, 6, 1,... is -54 ?
Solution :
Let -54 be the nth term of the sequence
tn = -54
a + (n - 1)d = -54
a = 16 , d = 11 - 16 ==> -5
16 + (n - 1)(-5) = -54
(n - 1)(-5) = -54 - 16
(n - 1)(-5) = -70
n - 1 = -70/(-5) ==> 14
n = 14 + 1
n = 15
Hence 15th term of the given sequence is -54.
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