# HOW TO IF THE PAIR OF STRAIGHT LINE IS PARALLEL OR PERPENDICULAR

## About "How to Check if the Pair of Straight line is Parallel or Perpendicular"

How to Check if the Pair of Straight line is Parallel or Perpendicular :

Here we are going to see how to check if the pair of straight line is parallel or perpendicular

Two straight lines represented by the equation ax2 + 2hxy + by2 + 2gx + 2fy + c = 0 are parallel if it satisfies one of the condition given below.

Method 1 :

Angle between a pair of straight lines

θ  =  tan-1 [2 √(h2 - ab)/(a + b)]

If two lines are parallel, then the angle between them will be 0.

If two lines are parallel, then the angle between them will be 90 degree.

Question 1 :

Find the combined equation of the straight lines whose separate equations are x − 2y −3 = 0 and x + y+5 = 0.

Solution :

Combined equation of straight lines :

=  (x − 2y −3)(x + y + 5)

=  x2 + xy + 5x - 2xy -  2y2 - 10y - 3x - 3y - 15

=  x2 - xy - 2y2 + 2x - 13y - 15

Question 2 :

Show that 4x2 + 4xy + y2 − 6x − 3y − 4 = 0 represents a pair of parallel lines.

Solution :

4x2 + 4xy + y2 − 6x − 3y − 4 = 0

By comparing the given equation with the general equation of pair of straight lines

ax2 + 2hxy + by2 + 2gx + 2fy + c = 0

We get, a  =  4, b  =  1, 2h  =  4  ==>  h  =  2

θ  =  tan-1 [2 √(22 - (4)(1))/(4 + 1)]

=  tan-1 [2 √(4 - 4)/5]

=  tan-1 [0]

=  0

Hence the given pair of straight line is parallel.

Question 3 :

Show that 2x2 + 3xy − 2y2 + 3x + y + 1 = 0 represents a pair of perpendicular lines.

Solution :

2x2 + 3xy − 2y2 + 3x + y + 1 = 0

By comparing the given equation with the general equation of pair of straight lines

ax2 + 2hxy + by2 + 2gx + 2fy + c = 0

We get, a  =  2, b  =  -2, 2h  =  3  ==>  h  =  3/2

If two lines are perpendicular then a + b  =  0

2 + (-2)  =  0

Hence the given pair of straight line is perpendicular.

After having gone through the stuff given above, we hope that the students would have understood "How to Check if the Pair of Straight Line is Parallel or Perpendicular".

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