# HARDEST SAT MATH QUESTIONS (Part - 7)

Question 1 :

g(x) = ax2 + 24

For the function g defined above, a is a constant and g(4) = 8. What is the value of g(-4) ?

(A) 8             (B) 0             (C) -1             (D) -8

Using the information given, first, we have to find the value of the 'a' in g(x) = ax2 + 24.

g(4)  =  8

ax2 + 24  =  8

a(4)2 + 24  =  8

16a + 24  =  8

16a  =  -16

a  =  -1

g(x) = -1x2 + 24

g(-4) = -1(-4)2 + 24

=  -1(16) + 24

=  -16 + 24

=  8

Question 2 :

If x > 3, which of the following is equivalent to

1 / [1/(x + 2) + 1/(x + 3)]

(A)  (2x + 5)/(x2 + 5x + 6)

(B)  (x2 + 5x + 6)/(2x + 5)

(C)  2x + 5

(D)  x2 + 5x + 6

Add 1/(x + 2) and 1/(x + 3).

1/(x + 2) + 1/(x + 3)  =  [(x + 2) + (x + 3)]/[(x + 2)(x + 3)]

=  (2x + 5)/(x2 + 5x + 6)

Then,

1 / [1/(x + 2) + 1/(x + 3)]  =  1 / [(2x + 5)/(x2 + 5x + 6)]

=  1  [(x2 + 5x + 6)/(2x + 5)]

=  (x2 + 5x + 6)/(2x + 5)

Question 3 :

If (ax + 2)(bx + 7) = 15x2 + cx + 14 for all values of x, and a + b = 8, what are the two possible values for c ?

A) 3 and 5

B) 6 and 35

C) 10 and 21

D) 31 and 41

(ax + 2)(bx + 7)  =  15x2 + cx + 14

abx2 + 7ax + 2bx + 14  =  15x2 + cx + 14

abx2 + (7a + 2b)x + 14  =  15x2 + cx + 14

Equate the coefficients of x2 and x.

ab  =  15

7a + 2b  =  c ----(1)

It is given that a + b = 8.

We have to find the values of a and b such that

a + b = 8  and  ab = 15

Possible options are :

a = 3 and b = 5

a = 5 and b = 3

 When a = 3 and b = 5, (1)---> 7(3) + 2(5)  =  c21 + 10  =  c31  =  c When a = 5 and b = 3, (1)---> 7(5) + 2(3)  =  c35 + 6  =  c41  =  c

Question 4 :

If 3x - y = 12, what is the value of 8x/2y ?

(A)  212

(B)  44

(C)  82

(D) The value cannot be determined from the information given.

8x/2y  =  (23)x/2y

=  23x/2y

=  23x - y

Substitute 3x - y = 12.

=  212

Question 5 : A summer camp counselor wants to find a length, x, in feet, across a lake as represented in the sketch above. The lengths represented by AB, EB, BD, and CD on the sketch were determined to be 1800 feet, 1400 feet, 700 feet, and 800 feet, respectively. Segments AC and DE intersect at B, and ∠AEB and ∠CDB have the same measure. What is the value of x ?

In ΔAEB and ΔCDE,

m∠AEB  =  m∠CDB (given)

m∠ABE  =  m∠CBD (vertical angles)

By AA Similarity Postulate, ΔAEB and ΔCDE are similar.

So, the corresponding sides are proportional.

AE/CD  =  BE/BD

Substitute AE = x, BE = 1400, BD = 700 and CD = 800.

x/800  =  1400/700

x/800  =  1400/700

x/800  =  2

Multiply each side by 800.

x  =  1600

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