GRAPHING LINEAR EQUATIONS USING INTERCEPTS

The following steps will be useful to graph a linear equation using intercepts. 

Step 1 :

Find the x-intercept by letting y = 0 and solving for x. Use the x-intercept to plot the point where the line crosses the x-axis.

Step 2 : 

Find the y-intercept by letting x = 0 and solving for y. Use the y-intercept to plot the point where the line crosses the y-axis.

Step 3 : 

Draw a line through the two points.

Use intercepts to graph the line described by each  equation.

Example 1 : 

2x + 3y  =  12

Solution : 

Find the intercepts.

x-intercept :

2x + 3y  =  12

2x + 3(0)  =  12

2x + 0  =  12

2x  =  12

2x/2  =  12/2

x  =  6

(6, 0)

y-intercept :

2x + 3y  =  12

2(0) + 3y  =  12

0 + 3y  =  12

3y  =  12

3y/3  =  12/3

y  =  4

(0, 4)

Plot (6, 0) and (0, 4).

Connect with a straight line.

Example 2 : 

-2x + 8y  =  16

Solution : 

Find the intercepts.

x-intercept :

-2x + 8y  =  16

-2x + 8(0)  =  16

-2x + 0  =  16

-2x  =  16

-2x/(-2)  =  16/(-2)

x  =  -8

(-8, 0)

y-intercept :

-2x + 8y  =  16

-2(0) + 8y  =  16

0 + 8y  =  16

8y  =  16

8y/8  =  16/8

y  =  2

(0, 2)

Plot (-8, 0) and (0, 2).

Connect with a straight line.

Example 3 : 

y  =  -0.5x - 1.5

Solution : 

Find the intercepts.

x-intercept :

y  =  -0.5x - 1.5

0  =  -0.5x - 1.5

0.5x  =  -1.5

x  =  -3

(-3, 0)

y-intercept :

y  =  -0.5x - 1.5

y  =  -0.5(0) - 1.5

y  =  0 - 1.5

y  =  -1.5

(0, -1.5)

Plot (-3, 0) and (0, -1.5).

Connect with a straight line.

Example 4  : 

y  =  2x/3 + 4

Solution : 

Find the intercepts.

x-intercept :

y  =  2x/3 + 4

0  =  2x/3 + 4

-4  =  2x/3

-12  =  2x

-6  =  x

(-6, 0)

y-intercept :

y  =  2x/3 + 4

y  =  2(0)/3 + 4

y  =  0/3 + 4

y  =  0 + 4

y  =  4

(0, 4)

Plot (-6, 0) and (0, 4).

Connect with a straight line.

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