**Question 1 :**

A certain freezing process requires that room temperature be lowered from 40°C at the rate of 5° C every hour. What will the room temperature 10 hours after the process begins?

(A) -4°C (B) -10°C (C) -3°C

**Solution :**

Room temperature = 40°C

It reduces the temperature level at the rate of 5°C per hour.

In one hour the temperature will become = 40 - 5 = 35

In two hours the temperature will become = 35-5 = 30

In ten hours the temperature will become = 40 - (10⋅5)

= 40 - 50

= -10°C

Hence room temperature after 10 hours is -10°C.

**Question 2 :**

In a class of 40 students 1/5 of the total number of students like to study English. Then how many students like to study English?

(A) 5 (B) 8 (C) 10

**Solution :**

Total number of students in the class = 40

In which 1/5 of the students would like to study English.

Number of students who would like to study English

= (1/5) of 40

= (1/5) ⋅ 40

= 8

Hence the number of students who would like to study English is 8.

**Question 3 :**

A two wheeler covers a distance of 55.3 km in one liter of petrol. How much distance will it cover in 10 liters of petrol?

(A) 553 km (B) 524 km (C) 320 Km

**Solution :**

Distance covered by two wheeler by consuming 1 liter petrol

= 55.3 km

Distance covered by two wheeler by consuming 10 liter petrol

= 55.3 (10)

= 553 km

**Question 4 :**

The ages in years of 10 teachers of a school are : 32, 41, 28, 54, 35, 26, 23, 33, 38, 40. What is the range of ages of the teachers?

(A) 31 years (B) 38 years (C) 40 years

**Solution :**

Range = L - S

Largest number = 54

Smallest number = 26

Range = 54 - 26 = 28

So, the range is 28.

**Question 5 :**

Find the value of p in the following equation 10p + 10 = 100

(A) 8 (B) 9 (C) 10

**Solution :**

10 p + 10 = 100

Subtract 10 on both sides

10 p = 90

Divide by 10 on both sides

p = 90/10 = 9

So, the value of p is 9.

**Question 6 :**

The teacher tells the class that the highest marks obtained by a student in her class is twice the lowest marks plus 7 . The highest score is 87.What will be the lowest score?

(A) 40 (B) 32 (C) 55

**Solution :**

Let "x" be the lowest mark

Highest mark obtained by the student = 2x + 7

2x + 7 = 87

Subtract 7 on both sides

2x = 87 - 7

2x = 80

Divide 2 on both sides

x = 80/2 = 40

So, the highest mark is 40.

**Question 7 :**

Find the angle x in the following picture.

**(A) 70° (B) 100° (C) 50°**

**Solution :**

Corresponding angles are equal.

So, the required angle is 100°.

**Question 8 :**

In triangle ABC right angled at C. If AC = 5 cm and BC = 12 cm find the length of AB.

(A) 12 cm (B) 18 cm (C) 13 cm

**Solution :**

In a right triangle ABC,

AB^{2} = AC^{2} + BC^{2}

AB^{2} = 12^{2} + 5^{2 }

AB^{2} = 144 + 25

AB^{2} = 169

AB = √169 = 13 cm

So, the length of hypotenuse side is 13 cm.

**Question 9 :**

Find the percent of the following picture which is colored.

(A) 37.5 % (B) 25.8 % (C) 50 %

**Solution :**

Out of 8 equal parts 3 parts are shaded

Percentage of the following picture which is colored

= (3/8) ⋅ 100

= 37.5%

**Question 10 :**

The perimeter of a rectangle is 130 cm. If the width of the rectangle is 30 cm, find the area of the rectangle.

(A) 6400 cm^{2} (B) 1050 cm^{2} (C) 3000 cm^{2}

**Solution :**

Perimeter of a rectangle = 130 cm

width = 30 cm

2(l + w) = 130

l + w = 65

l + 30 = 65

Subtract 30 on both sides

l = 65 - 30

L = 35 cm

Area of rectangle = L ⋅ w

= 35 ⋅ 30

= 1050 cm^{2}

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