Question 1 :
A certain freezing process requires that room temperature be lowered from 40°C at the rate of 5° C every hour. What will the room temperature 10 hours after the process begins?
(A) -4°C (B) -10°C (C) -3°C
Solution :
Room temperature = 40°C
It reduces the temperature level at the rate of 5°C per hour.
In one hour the temperature will become = 40 - 5 = 35
In two hours the temperature will become = 35-5 = 30
In ten hours the temperature will become = 40 - (10⋅5)
= 40 - 50
= -10°C
Hence room temperature after 10 hours is -10°C.
Question 2 :
In a class of 40 students 1/5 of the total number of students like to study English. Then how many students like to study English?
(A) 5 (B) 8 (C) 10
Solution :
Total number of students in the class = 40
In which 1/5 of the students would like to study English.
Number of students who would like to study English
= (1/5) of 40
= (1/5) ⋅ 40
= 8
Hence the number of students who would like to study English is 8.
Question 3 :
A two wheeler covers a distance of 55.3 km in one liter of petrol. How much distance will it cover in 10 liters of petrol?
(A) 553 km (B) 524 km (C) 320 Km
Solution :
Distance covered by two wheeler by consuming 1 liter petrol
= 55.3 km
Distance covered by two wheeler by consuming 10 liter petrol
= 55.3 (10)
= 553 km
Question 4 :
The ages in years of 10 teachers of a school are : 32, 41, 28, 54, 35, 26, 23, 33, 38, 40. What is the range of ages of the teachers?
(A) 31 years (B) 38 years (C) 40 years
Solution :
Range = L - S
Largest number = 54
Smallest number = 26
Range = 54 - 26 = 28
So, the range is 28.
Question 5 :
Find the value of p in the following equation 10p + 10 = 100
(A) 8 (B) 9 (C) 10
Solution :
10 p + 10 = 100
Subtract 10 on both sides
10 p = 90
Divide by 10 on both sides
p = 90/10 = 9
So, the value of p is 9.
Question 6 :
The teacher tells the class that the highest marks obtained by a student in her class is twice the lowest marks plus 7 . The highest score is 87.What will be the lowest score?
(A) 40 (B) 32 (C) 55
Solution :
Let "x" be the lowest mark
Highest mark obtained by the student = 2x + 7
2x + 7 = 87
Subtract 7 on both sides
2x = 87 - 7
2x = 80
Divide 2 on both sides
x = 80/2 = 40
So, the highest mark is 40.
Question 7 :
Find the angle x in the following picture.
(A) 70° (B) 100° (C) 50°
Solution :
Corresponding angles are equal.
So, the required angle is 100°.
Question 8 :
In triangle ABC right angled at C. If AC = 5 cm and BC = 12 cm find the length of AB.
(A) 12 cm (B) 18 cm (C) 13 cm
Solution :
In a right triangle ABC,
AB2 = AC2 + BC2
AB2 = 122 + 52
AB2 = 144 + 25
AB2 = 169
AB = √169 = 13 cm
So, the length of hypotenuse side is 13 cm.
Question 9 :
Find the percent of the following picture which is colored.
(A) 37.5 % (B) 25.8 % (C) 50 %
Solution :
Out of 8 equal parts 3 parts are shaded
Percentage of the following picture which is colored
= (3/8) ⋅ 100
= 37.5%
Question 10 :
The perimeter of a rectangle is 130 cm. If the width of the rectangle is 30 cm, find the area of the rectangle.
(A) 6400 cm2 (B) 1050 cm2 (C) 3000 cm2
Solution :
Perimeter of a rectangle = 130 cm
width = 30 cm
2(l + w) = 130
l + w = 65
l + 30 = 65
Subtract 30 on both sides
l = 65 - 30
L = 35 cm
Area of rectangle = L ⋅ w
= 35 ⋅ 30
= 1050 cm2
If you need any other stuff in math, please use our google custom search here.
Kindly mail your feedback to v4formath@gmail.com
We always appreciate your feedback.
©All rights reserved. onlinemath4all.com
Apr 25, 24 08:40 PM
Apr 25, 24 08:13 PM
Apr 25, 24 07:03 PM