**Grade 6 Math Worksheet with Answers :**

In this section, we will see some practice problems for 6th grade students.

**Question 1 :**

A gardener plans to plant 570 trees in 19 rows. Each row is to contain the same number of trees. How many trees will there be in each row ?

(A) 15 (B) 17 (C) 30

**Solution :**

Number of trees = 570

Number of rows = 19

Each row is containing same number of trees.

Number of trees in each row = 570/19

= 30

Hence 30 trees in each row.

**Question 2 :**

The population of a town is 450772. 1 out of every 14 persons is reported to be educated. In all, how many educated persons are there in the town.

(A) 32198 (B) 45123 (C) 15465

**Solution :**

Total population = 450772

Number of educated persons = 450772/14

= 32198

Hence the number of educated persons is 32198.

**Question 3 :**

The LCM of 20, 25, 30 and 40.

(A) 700 (B) 600 (C) 300

**Solution :**

Least common multiple = 5 x 2 x 2 x 5 x 3 x 2

= 600

**Question 4 :**

Given that LCM of two numbers is 16 and their product is 64, determine their HCF.

(A) 15 (B) 4 (C) 12

**Solution :**

Product of two numbers = L.C.M x H.C.F

l.C.M = 16, H.C.F = ?, product of two numbers = 64

64 = 16 x H.C.F

H.C.F = 64/16

H.C.F = 4

**Question 5 :**

The number of boys and girls in a school are 480 and 576 respectively. Express the ratio of the number of boys to that girls in the simplest form.

(A) 5:6 (B) 6:5 (C) 2:3

**Solution :**

Number of boys : Number of girls

= 480 : 576

= 480/576

= 5/6

= 5 : 6

**Question 6 :**

Find the third term of a proportion whose first, second and fourth terms are respectively 24, 8 and 5

(A) 20 (B) 18 (C) 15

**Solution :**

Let x be the third term.

24 : 8 :: x : 5

Product of extremes = Product of means

24 ⋅ 5 = 8 ⋅ x

x = (24 ⋅ 5)/8

x = 15

**Question 7 :**

Find 20% of 150

(A) 30 (B) 16 (C) 25

**Solution :**

20% of 150 = (20/100) ⋅ 150

= 30

**Question 8 :**

Find the value of 2y^{3 }- 3y^{2} + y - 1, if y = -2

(A) -15 (B) -65 (C) -31

**Solution :**

p(y) = 2y^{3 }- 3y^{2} + y - 1

p(-2) = 2(-2)^{3 }- 3(-2)^{2} + (-2) - 1

= 2(-8) - 3(4) - 2 - 1

= -16 - 12 - 3

= -31

Hence the answer is -31.

**Question 9 :**

Sum of the three angles of a triangle is ________

(A) 150° (B) 180° (C) 120°

**Solution :**

The sum of the interior angles of a triangle is 180°.

**Question 10 :**

A tile is a square of side 25 cm. How many such tiles would be required to cover the floor of a square bath room of side is 3 m ?

(A) 13 (B) 17 (C) 12

**Solution :**

Number of square tiles = Area of bath room / Area of one square tile

Area of bath room = 3 m = 3 x 100 = 300 cm

Number of tiles = 300/25

= 12

After having gone through the stuff given above, we hope that the students would have practiced problems in the worksheet.

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