


Geometry Practice Questions
Geometry Practice Questions  Solved
2 x = 24 ^{0} (Alternate angles are equal) x = 24/2 There fore x = 12^{0} Problem:2 Find the following angles Solution: Here we are having two angles x degree and 3x degree. X ° + 3x° = 180 (Angle in a straight line) 4x° = 180 X°= 180 /4 X°= 45° Then 3x° = 3(45°) Therefore the angles are 45° and 135° Explanation: 1.Here we have straight line and it has divided into two parts.
X°+(x+20°) = 90 (Because it is right angle) 2x°+20° = 90 (subtract 20 from 90) 2x° = 70° (Divide 70° by 2) x° = 70°/2 x° = 35° x°+20 = 35° + 20° = 55° Therefore the angels are 35° and 55° Explanation: 1.Here we have two angles x° and x+20° (both are adjacent angles) Problem 4 Geometry problem using obtuse angle Find the following angles if angle AOB = 120 °
(3x °20°) + x ° = 120° 3x°20° + x° = 120° 4x°20° = 120° (Add 20° with 120°) 4x° = 120 °+ 20° 4x° = 140° (Divide 140 by 4) x° = 140°/4 x° = 35° 3x°  20° = 3(35°)20° = 105°20° = 85° Therefore the angles are 35° and 85°
Problem:5 Geometry problem using the concept transversal line Find the value of x and y
x ° + y° = 180° (straight angle) (Plug x = 130°) 130° + y° = 180° (Subtract 130 from 180) Y° = 180° 130° Y° = 50° Therefore the two angles are 130° and 50° These are only few problems given on the topic Geometry practice questions.Apart from the problems that you find here, we have lots of problems in the topic geometry practice questions. 
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