Geometry Practice Questions





Geometry Practice Questions is the place where we can have some geometry pictures, geometry questions, geometry nature and practice problems to improve our stuff on the topic geometry.The problems given here would be much helpful for the students who are in the preparation of the topic geometry for exams.Let us look at some problems in the topic geometry practice questions.

Geometry Practice Questions - Solved


Problem:1
Find x and y from the following figures

Solution:
AB = DC, AD = BC (given)
ABCD is a parallelogram

2 x = 24 0 (Alternate angles are equal)

x = 24/2
x = 12
3y = 60 0 (alternate angles are equal)
y = 60/3
y = 30

There fore x = 120
and y = 300


Explanation:

1.ABCD is the parallelogram.
2.Here the sides AB is parallel to the side CD and AC is the transversal line.
3.The angles BAC and ACD are alternate interior angles.And the angles DAC and BCA are measuring equal.so they are equal.
4.so that 2x=24 & 3y = 60.if w simplify we will get the value of x and y.



Problem:2
Find the following angles

Solution:

Here we are having two angles x degree and 3x degree.

X ° + 3x° = 180 (Angle in a straight line)

4x° = 180

X°= 180 /4

X°= 45°

Then 3x° = 3(45°)
= 135°

Therefore the angles are 45° and 135°

Explanation:

1.Here we have straight line and it has divided into two parts.
2.We know the angle of straight line is 180°.
3.So let us add x° and 3x° and equate with 180°.
4.If we simplify them we got the angles 45° and 135°.



Problem:3
Geometry problems using right angle Find the angles in the following questions



Solution:

Here we have two angles x° and x+20°

X°+(x+20°) = 90 (Because it is right angle)

2x°+20° = 90

(subtract 20 from 90)

2x° = 70°

(Divide 70° by 2)

x° = 70°/2

x° = 35°

x°+20 = 35° + 20°

= 55°

Therefore the angels are 35° and 55°

Explanation:

1.Here we have two angles x° and x+20° (both are adjacent angles)
2.From the figure we come to know it is right angle and it must be 90°
3.x°+(x°+20)= 90°
4.Let us solve for x . so we got 35°.Now we need to find the another angle also
5.That is x+20 .Here x=35 .so 35+ 20 =55°.There fore another angle = 55°.


Problem 4
Geometry problem using obtuse angle
Find the following angles if angle AOB = 120 °


Solution:
Here the total angle that is AOB is given
Angle AOD + Angle DOB = 120° (given)

(3x °-20°) + x ° = 120°

3x°-20° + x° = 120°

4x°-20° = 120°

(Add 20° with 120°)

4x° = 120 °+ 20°

4x° = 140°

(Divide 140 by 4)

x° = 140°/4

x° = 35°

3x° - 20° = 3(35°)-20°

= 105°-20°

= 85°

Therefore the angles are 35° and 85°

Explanation:
1.The total angle is 120° it is given
2.so let us add x° with 3x°-20.
3.simplifying this we got 35° for x°
4.And plug the same for x° in 3x°-20°
5.we got 85° as another angle


Problem:5
Geometry problem using the concept transversal line
Find the value of x and y



Solution:

Here L1 and L2 are parallel lines and L3 is a transverse X° = 130° (because alternate interior angles will be equal)

x ° + y° = 180° (straight angle)

(Plug x = 130°)

130° + y° = 180°

(Subtract 130 from 180)

Y° = 180° -130°

Y° = 50°

Therefore the two angles are 130° and 50°

Explanation:
1.Here the lines L1 and L2 are parallel and L3 is the transversal
2.X° is alternate interior angle to 130° both are equal.
3.The sum of x° and y° is 180 because it is straight line
4.Let us plug the value 130 in equation x +y =180



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