The Fundamental Theorem of Calculus (Part-1) is an extremely powerful theorem that establishes the relationship between differentiation and integration.
If f(x) is continuous over an interval [a, b], and the function F(x) is defined by
Then the derivative of F(x) is
F'(x) = (x)'f(x) - (a)'f(a)
Using the First Fundamental Theorem of Integral Calculus, find the derivative of g(x) in each case.
Example 1 :
Solution :
Example 2 :
Solution :
Example 3 :
Solution :
Example 4 :
Solution :
g'(x) = (x3)'(cos x3) - (1)'(cos 1)
g'(x) = (3x2)(cos x3) - (0)(cos 1)
g'(x) = 3x2cos x3
Example 5 :
Solution :
g'(x) = (2x)'[(2x)3] - (x)'(x3)
g'(x) = (2)(8x3) - (1)(x3)
g'(x) = 16x3 - x3
g'(x) = 15x3
Example 6 :
Solution :
g'(x) = (x3)'(cos x3) - (x)'(cos x)
g'(x) = (3x2)(cos x3) - (1)(cos x)
g'(x) = 3x2cos x3 - cos x
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