We can find the volume of a sphere using the volume of a cylinder.
Cylinder is a solid which has a circular base.
We know the fact that the volume of any solid is equal to the product of base area and height of the solid.
So, the volume of a right circular cylinder of base radius ‘r’ and height ‘h’ is given by
V = (Base Area) x (Height)
The base of a cylinder is a circle, so for a cylinder,
Base Area = πr2
Therefore,
Volume of a cylinder = πr2h cubic units
Consider a right circular cylinder and three right circular cones of same base radius and height as that of the cylinder.
The contents of three cones will exactly occupy the cylinder.
Then,
When we model the volume of a sphere, we will be getting the following result.
3 x (Volume of a cone) = Volume of cylinder
3 x (Volume of a cone) = πr2h
Volume of the cone = 1/3 · πr2h cubic units
Consider a sphere and two right circular cones of same base radius and height such that twice the radius of the sphere is equal to the height of the cones.
Then we can observe that the contents of two cones will exactly occupy the sphere.
Then,
Volume of sphere = 2 x (Volume of a cone)
Volume of a sphere = 2 x (1/3 · πr2h)
Volume of a sphere = 2/3 · πr2h
A sphere always has a height which is equal to twice the radius.
So, substitute 2r for h.
Volume of sphere = 2/3 · πr2(2r)
Simplify.
Volume of sphere = 4/3 · πr3 cubic units
Example 1 :
Find the volume of the sphere given below. Round your answer to the nearest tenth if necessary. Use the approximate of value of π, that is 3.14.
Solution :
Step 1 :
Write the formula to find volume of a sphere.
V = 4/3 · πr3
Step 2 :
Substitute the given measures.
V ≈ 4/3 · 3.14 · (2.2)3
Simplify.
V ≈ 4/3 · 3.14 · 10.648
V ≈ 44.6
So, the volume of the given sphere is about 44.6 cubic cm.
Example 2 :
Find the volume of the sphere given below. Round your answer to the nearest tenth if necessary. Use the approximate of value of π, that is 3.14.
Solution :
Step 1 :
Write the formula to find volume of a sphere.
V = 4/3 · πr3 -----(1)
Step 2 :
To find the volume, we need the radius of the sphere. But, the diameter is given, that is 42 cm. So, find the radius.
r = diameter/2
r = 42/2
r = 21
Step 3 :
Substitute π ≈ 3.14 and r = 21 in (1).
V ≈ 4/3 · 3.14 · 213
Simplify.
V ≈ 4/3 · 3.14 · 9261
V ≈ 38,772.7
So, the volume of the given sphere is about 38,772.7 cubic cm.
Example 3 :
Find the volume of the sphere given below. Round your answer to the nearest tenth if necessary. Use the approximate of value of π, that is 3.14.
Solution :
Step 1 :
Write the formula to find volume of a sphere.
V = 4/3 · πr3 -----(1)
Step 2 :
To find the volume, we need the radius of the sphere. But, the height is given, that is 12 cm.
We know that the height of a sphere equals twice the radius.
That is,
h = 2r
Substitute h = 12.
12 = 2r
Divide both sides by 2.
12/2 = 2r/2
6 = r
Step 3 :
Substitute π ≈ 3.14 and r = 6 in (1).
V ≈ 4/3 · 3.14 · 63
Simplify.
V ≈ 4/3 · 3.14 · 216
V ≈ 904.3
So, the volume of the given sphere is about 904.3 cubic cm.
Example 4 :
Two spheres M and N have volumes of 250 cubic cm and 750 cubic cm respectively. Find the ratio of their radii.
Solution :
Let r1 and r2 be the radii of two spheres M and N.
(4/3) πr13 : (4/3) πr23 = 250 : 750
r13 : r23 = 250 : 750
r13 / r23 = 250 / 750
(r1 / r2)3 = 25 / 75
(r1 / r2) = ∛(25 / 75)
(r1 / r2) = ∛(25/3x25)
(r1 / r2) = ∛(1/3)
(r1 / r2) = 1/∛3
r1 : r2 = 1 : ∛3
Example 5 :
Fifty metal spheres with the radii of 4 m are melted and this melted solution is poured into a cube with base dimensions of 2 m × 6 m. Find the height of the cube filled with solution
Solution :
Volume of 50 metal spheres = volume of cube
50 · (4/3) πr3 = l x w x h
50 · (4/3) π(4)3 = 2 x 6 x h
(12800/3)π = 2 x 6 x h
h = (12800/3 x 2 x 6)π
h = 1116.4
Approximately the required height is 1117 m.
Example 6 :
A hemisphere is one-half of a sphere. The top of the silo is a hemisphere with a radius of 12 feet. What is the volume of the silo? Round your answer to the nearest thousand.
Solution :
Hemisphere = 1/2 of sphere
radius = 12 feet
Volume of hemispere = (1/2) · (4/3) πr3
= (2/3) πr3
= (2/3) π(2)3
= 16π/3 ft3
Example 7 :
Two metal cubes with sides of 4 cm are melted and casted into a spherical ball. Find the radius of sphere so formed.
Solution :
Volume of 2 metal cubes = Volume of sphere
2 (side x side x side) = (4/3) πr3
2 (4 x 4 x 4) = (4/3) πr3
6 x 4 x 4 = πr3
96/3.14 = r3
r3 = 30.15
r = 3.13 cm
So, the radius of the sphere is 3.13 cm.
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