FINDING THE SUM OF GIVEN NUMBER OF TERMS FROM THE GIVEN INFORMATION

Finding the Sum of Given Number of Terms from the Given Information :

In this section, we will see some example problems with mixed information based on the topic arithmetic series.

Finding the Sum of Given Number of Terms from the Given Information - Examples

Question 1 :

Given a = 7, a₁₃ = 35 find d and S₁₃  

Solution :

13^th term of the arithmetic progression,

a₁₃  =  35

a + 12d  =  35 ---(1)

By applying the value of a in (1), we get d

7 + 12d  =  35

12d  =  35 - 7

12d  =  28

d  =  28/12  =  14/6  =  7/3

S_n  =  (n/2) [2a + (n - 1)d]

S₁₃  =  (13/2) [2(7) + (13 - 1)(7/3)]

S₁₃  =  (13/2) [14 + 12(7/3)]

S₁₃  =  (13/2) [14 + 28]

S₁₃  =  (13/2) (42)

S₁₃  =  273

Hence, the sum of 13 terms of the arithmetic progression is 273.

Question 2 :

Given a₁₂ = 37, d = 3 find a and S₁₂ 

Solution :

12^th term of AP :

a₁₂ = 37

a + 11d  =  37 -----(1)

By applying the value of d in (1), we get

a + 11(3)  =  37

a + 33  =  37

a  =  37 - 33  =  4

Now, we find the sum of 12 terms

s_n  =  (n/2)[2a + (n - 1|)d]

s₁₂  =  (12/2)[2(4) + (12 - 1)(3)]

s₁₂  =  6[8 + 11(3)]

s₁₂  =  246

Hence, the sum of first 12 terms is 246.

Question 3 :

Given a₃ = 15 , S₁₀ = 125 find d and a₁₀  

Solution :

Here, we have 3^rd term and sum of first 10 terms. By using these information, we should find the common difference and 10^th term.

a₃ = 15

a + 2d  =  15  ----(1)

S₁₀ = 125

S_n  =  (n/2)[2a + (n - 1)d]

Here, n = 10

(10/2)[2a + (10 - 1)d]  =  125

5[2a + 9d]  =  125

Dividing each side by 5.

2a + 9d  =  25  ----(2)

By solving (1) and (2), we will get the values of a and d.

(1) ⋅ 2 - (2)

2a + 4d  =  10

2a + 9 d  =  25

(-)     (-)     (-) 

--------------------

-5d  =  -15

d  =  3

By applying the value of d in (1), we get

a + 2(3)  =  15

a + 6  =  15

a  =  15 - 6  =  9

10^th term :

a₁₀  =  a + 9d

a₁₀  =  9 + 9(3)

=  9 + 27

a₁₀  =  36

Hence, the 10^th term is 36.

After having gone through the stuff given above, we hope that the students would have understood, finding the sum of given number of terms from the given information

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