# FINDING THE INDICATED TERM OF A SEQUENCE

## About "Finding the Indicated Term of a Sequence"

Finding the Indicated Term of a Sequence :

Here we are going to see some practice questions to find the indicated term of the sequence.

## Finding the Indicated Term of a Sequence ?

Question 1 :

Find the indicated terms of the sequences whose nth terms are given by

(i) an  =  5n / (n + 2); a6 and a13

Solution :

To find a6, we have to apply 6 instead of n.

To find a13, we have to apply 13 instead of n.

 an  =  5n / (n + 2)n = 6 a6  =  5(6)/(6 + 2)  =  30/8 a6  =  15/4 an  =  5n / (n + 2)n = 13 a13  =  5(13)/(13 + 2)  =  65/15 a13  =  13/3

(ii) a =  -(n2 - 4); a4 and a11

Solution :

To find a4, we have to apply 4 instead of n.

To find a11, we have to apply 11 instead of n.

 an  =   -(n2 - 4)n = 4 a4  =   -(42 - 4) a4  =   -(16 - 4)=  -12 an  =   -(n2 - 4)n = 11 a11  =   -(112 - 4) a11  =   -(121 - 4)=  -117

Question 2 :

Find a8 and a15 whose nth term is

Solution :

In a8, 8 is even in a15, 15 is odd

 an  =  (n2 - 1)/(n + 3)a8  =  (82 - 1)/(8 + 3)  =  (64 - 1)/11  =  63/11 an  =  n2/(2n + 1)a15  =  152/(2(15) + 1)  =  225/(30 + 1)  =  225/31

Question 3 :

If a1 = 1, a2 = 1 and an = 2an - 1 + an - 2≥ 3, n ∈ N, then find the first six terms of the sequence.

Solution :

First and second terms are 1.

an = 2an - 1 + an - 2

 n = 3an = 2an - 1 + an - 2 a3 = 2a3-1 + a3-2 a3  =  2a2 + a1a3  =  2(1) + 1a3  =  3 n = 4an = 2an - 1 + an - 2 a4 = 2a4-1 + a4-2 a4  =  2a3 + a2a4  =  2(3) + 1a4  =  7 n = 5an = 2an - 1 + an - 2 a5 = 2a5-1 + a5-2 a5  =  2a4 + a3a5  =  2(7) + 3a5  =  17 n = 6an = 2an - 1 + an - 2 a6 = 2a6-1 + a6-2 a6  =  2a5 + a4a5  =  2(17) + 7a5  =  41

Hence the first 6 terms are 1, 1, 3, 7, 17, 41.

After having gone through the stuff given above, we hope that the students would have understood, "Finding the Indicated Term of a Sequence".

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