**Finding the area of a trapezoid :**

The area of a trapezoid is half its height multiplied by the sum of the lengths of its two bases.

**A = (1/2) h (b₁ + b₂)**

Going through the history of ancient period and also that of medieval period, we do find the mention of statistics in many countries.

Notice that two copies of the same trapezoid fit together to form a parallelogram. The height of the parallelogram is the same as the height of the trapezoid.

The length of the base of the parallelogram is the sum of the lengths of the two bases (b₁ and b₂**)** of the trapezoid.

So, the area of a trapezoid is half the area of the parallelogram.

**Example 1 :**

A section of a deck is in the shape of a trapezoid. What is the area of this section of the

**Solution :**

here b₁ = 17 ft, b₂ = 39 ft and h = 16 ft

Area of trapezoid = (1/2) h (b₁ + b₂)

Substituting the above values in the formula, we get

= (1/2) x 16 (17 + 39)

= 8 (56) = 448 square ft

**Example 2 :**

The length of one base of a trapezoid is 27 feet, and the length of the other base is 34 feet. The height is 12 feet. What is its area?

**Solution :**

here b₁ = 27 ft, b₂ = 34 ft and h = 12 ft

Area of trapezoid = (1/2) h (b₁ + b₂)

Substituting the above values in the formula, we get

= (1/2) x 12 (34 + 27)

= 6 (61) = 366 square ft

**Example 3 :**

Simon says that to find the area of a trapezoid, you can multiply the height by the top base and the height by the bottom base. Then add the two products together and divide the sum by 2. Is Simon correct? Explain your answer.

**Solution :**

Yes;

Simon uses the Distributive Property to multiply each base by the height. Then he finds the sum BY multiplying by 1/2 is the same as dividing by 2

**Example 4 :**

The height of a trapezoid is 8 in. and its area is 96 square inches. One base of the trapezoid is 6 inches longer than the other base. What are the lengths of the bases?

**Solution :**

here, h = 8 inches

Area of the trapezoid = 96 square inches

base lengths are b₁ and b₂ respectively.

b₁ = b₂ + 6

(1/2) x 8 (b₂ + 6 + b₂) = 96

4 (2b₂ + 6) = 96

2b₂ + 6 = 24

2b₂ = 18

b₂ = 9

By applying the value of b₂ in the equation b₁ = b₂ + 6, we get

b₁ = 9 + 6 ==> b₁ = 15 inches

Hence, base lengths are 9 inches and 15 inches

- Area and polygons
- Inverse operations
- Area of square and rectangles
- Area of quadrilaterals
- Area of a parallelogram
- Finding the area of a trapezoid
- Finding the area of a rhombus
- Area of triangles
- Finding the area of a triangle
- Problems using area of a triangles
- Solving area equations
- Writing equations using the area of a trapezoid
- Solving multistep problems
- Area of polygons
- Finding areas of polygons
- Real world problems involving area and perimeter of polygon

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