**Finding Percent Increase Worksheet :**

Worksheet given in this section will be much useful for the students who would like to practice solving problems on percentage increase.

**Problem 1 : **

Due to increase in demand, the price of an item is increased from 80 cents to 1.4 dollars. Find the percentage increase in price.

**Problem 2 : **

Sally is in a long-jump competition. Her first jump and second jump are 5.6m and 6.3m respectively. Find the percentage increase in her jump length.

**Problem 3 : **

6 months ago the height of a plant was 12 inches and. The height of the plant today is 4 feet. Find the percentage change in height.

**Problem 4 : **

The length and width of a rectangle are increased by 10% and 5% respectively. Find the percentage increase in area.

**Problem 5 : **

In a triangle, if the height is increased by 50%, what percentage of the area will be increased ?

**Problem 1 : **

Due to increase in demand, the price of an item is increased from 80 cents to 1.4 dollars. Find the percentage increase in price.

**Solution :**

Amount of change = 1.4 dollars - 80 cents

= 140 cents - 80 cents

= 60 cents

Percentage change is

= (Amount of change / Original amount) x 100 %

= (60 / 80) ⋅ 100%

= 75%

So, the percentage increase in price of the item is 75.

**Problem 2 : **

Sally is in a long-jump competition. Her first jump and second jump are 5.6m and 6.3m respectively. Find the percentage increase in her jump length.

**Solution :**

Amount of change = Greater value - Lesser value

= 6.3 - 5.6

= 0.7

Percentage change is

= (Amount of change / Original amount) x 100 %

= (0.7 / 5.6) ⋅ 100%

= 12.5%

So, the percentage increase in her jump length is 12.5.

**Problem 3 : **

6 months ago the height of a plant was 12 inches and. The height of the plant today is 4 feet. Find the percentage change in height.

**Solution :**

Amount of change :

= 4 feet - 12 inches

= (4 ⋅ 12) inches - 12 inches

= 48 inches - 12 inches

= 36 inches

Percentage change is

= (Amount of change / Original amount) ⋅ 100 %

= (36 / 12) ⋅ 100%

= 3 ⋅ 100%

= 300%

So, the height of the plant is increased by 300%.

**Problem 4 : **

The length and width of a rectangle are increased by 10% and 5% respectively. Find the percentage increase in area.

**Solution :**

Let l and w be the original length and width of the rectangle.

Then, the area is lw.

After the length and width of the rectangle are increased by 10% and 5% respectively, the area is

= (1.1l)(1.05w)

= 1.155lw

Amount of change = Greater value - Lesser value

= 1.155lw - lw

= 0.155lw

Percentage change is

= (Amount of change / Original amount) ⋅ 100 %

= (0.155lw / lw) ⋅ 100%

= 0.155 ⋅ 100%

= 15.5%

So, the area of the rectangle will be increased by 15.5%.

**Problem 5 : **

In a triangle, if the height is increased by 50%, what percentage of the area will be increased ?

**Solution :**

Let b and h be the original base and height of the triangle respectively.

Then, the area of the triangle is

= bh / 2

= 0.5bh

If the height is increased by 50%, then the area of the triangle is

= b(1.5h) / 2

= 1.5bh / 2

= 0.75bh

Amount of change :

= 0.75bh - 0.5bh

= 0.25

Percentage change is

= (Amount of change / Original amount) ⋅ 100 %

= (0.25bh / 0.5bh) ⋅ 100%

= (0.25 / 0.5) ⋅ 100%

= 50%

So, the area of the triangle will be increased by 50%.

After having gone through the stuff given above, we hope that the students would have understood, how to do problems on percentage increase.

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