FINDING GCD OF POLYNOMIALS EXAMPLES

To find the GCD by Factorisation

(i) Each expression is to be resolved into factors fi rst.

(ii) Th e product of factors having the highest common powers in those factors will be the GCD.

(iii) If the expression have numerical coefficient, find their GCD separately and then prefix it as a coefficient to the GCD for the given expressions.

Example 1 :

Find the GCD for the following:

(i)  p5, p11, p9

Solution :

The minimum term of given terms,

  =  p5

Hence the required GCD is p5

(ii)  4x3, y3, z3

Solution :

There is not common term for the given three terms.

Hence GCD is 1.

(iii)  9 abc3, 15 abc4

Solution :

9 abc=  32 a⋅  b⋅ c3

15 abc=  3 ⋅ a⋅  b⋅ c4

G.C.D  =  3a2 bc3

(iv)  64x8, 240x6

Solution :

 64  =  2 and 240  =  24 ⋅ 5 ⋅ 3

G.C.D  =  24 x  =  16x6

Hence the required G.C.D is 16x6.

(v)  ab2c3, a2b3c, a3bc2

Solution :

 ab2c3, a2b3c, a3bc2

Hence GCD is abc.

(vi)  35 x5 y3 z4, 49 xy z3, 14 x yz2

Solution :

35  = ⋅ 7

49  =  72

14  =  2 ⋅ 7

  =  7 xy z3

Hence the GCD is 7 xy z3.

(vii)  25ab3c, 100 a2bc, 125 ab

Solution :

25ab3c  =  52ab3c  

100 a2bc  = 22 ⋅ 52 a2bc

125 ab  =  53 ab

GCD  =  52 ab  =  25ab

Hence GCD is 25ab.

(viii)  3 abc, 5 xyz, 7 pqr

Solution :

There is no common terms, hence the GCD is 1.

Example 2 :

Find the GCD of the following:

(i) (2x +5), (5x +2)

Solution :

The given polynomials are different, since they have no common terms.

G.C.D is 1.

(ii)  am + 1, am + 2, am + 3

Solution :

The common term is am + 1

Hence GCD is am + 1.

(iii)  2a2 + a, 4a2 - 1

Solution :

2a2 + a  =  a(2a + 1)

4a2 - 1  =  (2a)2 - 12

  =  (2a + 1)(2a - 1)

Hence GCD is 2a + 1.

(iv)  3a2, 5b3, 7c4

Solution :

Hence the GCD is 1.

(v)  x4 - 1, x2 - 1

Solution :

x4 - 1  =  (x2)2 - (12)2

  =  (x2 + 1)(x2 - 1)

  =  (x2 + 1)(x + 1)(x - 1)

x2 - 1  =  (x + 1) (x - 1)

Hence GCD is (x + 1) and (x - 1).

(vi)  a3 - 9ax2, (a - 3x)2

Solution :

a3 - 9ax =  a(a2 - 9x2)

  =  a(a2 - (3x)2)

  =  a (a + 3x) (a - 3x)

(a - 3x)2  =  (a  - 3x)(a - 3x)

Hence the GCD is (a  - 3x).

Kindly mail your feedback to v4formath@gmail.com

We always appreciate your feedback.

©All rights reserved. onlinemath4all.com

Recent Articles

  1. SAT Math Resources (Videos, Concepts, Worksheets and More)

    Oct 01, 24 12:04 PM

    SAT Math Resources (Videos, Concepts, Worksheets and More)

    Read More

  2. Digital SAT Math Problems and Solutions (Part - 47)

    Oct 01, 24 11:49 AM

    Digital SAT Math Problems and Solutions (Part - 47)

    Read More

  3. Digital SAT Math Problems and Solutions (Part - 46)

    Sep 30, 24 11:38 AM

    digitalsatmath41.png
    Digital SAT Math Problems and Solutions (Part - 46)

    Read More