Domain :
The domain of a function f(x) is the set of all values for which the function is defined
Range :
The range of the function is the set of all values that f takes.
They may also have been called the input and output of the function.) .
It is like evaluating functions for the given value of x.
Example 1 :
Consider f(x) = x2 for the domain {-2, -1, 0, 1, 2}
Find the range.
Solution :
Given, f(x) = x2
If x = -2 f(-2) = (-2)2 f(-2) = 4 |
If x = -1 f(-1) = (-1)2 f(-1) = 1 |
If x = 0 f(0) = (0)2 f(0) = 0 |
If x = 1 f(1) = 12 f(1) = 1 |
If x = 2 f(2) = (2)2 f(2) = 4 |
Range = {4, 1, 0, 1, 4}
Example 2 :
For the following functions of
f : x -> f(x) on -2≤x≤2
where x ∈ z
(a) List the elements of the domain of f(x) using set notation.
(b) List the elements of the range of f(x) using set notation.
(1) f(x) = 1/(x+3)
(2) (x+3)/x and x ≠ 0
(3) f(x) = 3x
(1) Solution :
Given :
f(x) = 1/(x+3)
Domain = {-2, -1, 0, 1, 2}
f(x) = 1/(x+3) If x = -2 f(-2) = 1/(-2+3) f(-2) = 1 |
If x = -1 f(-1) = 1/(-1+3) f(-1) = 1/2 |
If x = 0 f(0) = 1/(0+3) f(0) = 1/3 |
If x = 1 f(1) = 1/(1+3) f(1) = 1/4 |
If x = 2 f(2) = 1/(2+3) f(2) = 1/5 |
Range = {1, 1/2, 1/3, 1/4, 1/5}
(2) Solution :
Given :
f(x) = (x+3)/x
Domain = {-2, -1, 0, 1, 2}
f(x) = (x+3)/x If x = -2 f(-2) = (-2+3)/(-2) f(-2) = -1/2 |
If x = -1 f(-1) = (-1+3)/(-1) f(-1) = -2 |
If x = 1 f(1) = (1+3)/1 f(1) = 4 |
If x = 2 f(2) = (2+3)/2 f(2) = 5/2 |
Range = {-1/2, -2, 5/2, 4}
(3) Solution :
Given :
f(x) = 3x
Domain = {-2, -1, 0, 1, 2}
f(x) = 3x If x = -2 f(-2) = 3-2 f(-2) = 1/32 f(-2) = 1/9 |
If x = -1 f(-1) = 3-1 f(-1) = 1/3 |
If x = 0 f(0) = 30 f(0) = 1 |
If x = 1 f(1) = 31 f(1) = 3 |
If x = 2 f(2) = 32 f(2) = 9 |
Range = {1/9, 1/3, 1, 3, 9}
Example 3 :
Find the range of f (x) = −x + 4 for the
domain {–3, –2, –1, 1}
Solution :
To find range of the given function from the given domain, we have to apply the given values one by one in the given function.
f(x) = −x + 4
x = -3 f(-3) = −(-3) + 4 = 3 + 4 = 7 |
x = -2 f(-2) = −(-2) + 4 = 2 + 4 = 6 |
x = -1 f(-1) = −(-1) + 4 = 1 + 4 = 5 |
x = 1 f(1) = −1 + 4 = 3 |
So, the range is {7, 6, 5, 3}.
Example 4 :
To rent a bike, Max pays a at rate plus an hourly rental fee. The graph shows the amount, c dollars, he pays based on the number of hours, t, he uses the bike. Use the graph to answer the following question:
What is the domain and range of the function?
Solution :
Domain of the function 0 ≤ h < ∞
Range is 5 ≤ c < ∞
Example 5 :
A car rental company charges $10 an hour (a part of an hour rounds up to the next hour) to rent a car. The limit to the number of hours you can rent the car is 8 hours.
a. Write a rule in function notation for this situation.
b. What is a reasonable domain and range for this situation?
c) The graph will be discrete or continuous.
Solution :
a) Let x be the number of hours of renting car.
Let f(x) be the cost paid for renting car.
Cost of renting 1 hour = $10
The required function will be,
f(x) = 10x
b. The minimum number of hours of renting car is 0 and maximum number of hours of renting car. Number of hours rented should be whole number.
So, domain is {0, 1, 2, 3, 4, 5, 6, 7, 8}
When h = 0, f(0) = 0
When h = 1, f(1) = 10
When h = 2, f(2) = 20
and so on
So, range is {0, 10, 20, 30, 40, 50, 60, 70, 80}
c) The graph should be discrete, because we can pay every hours and it should be whole numbers not a decimal.
Example 5 :
The American Sycamore tree grows approximately 6 feet per year until they reach a maximum height of 66 ft.
a. Write a rule in function notation for this situation.
b. What is a reasonable domain and range for this situation?
c) The graph will be discrete or continuous.
Solution :
a) Let x be the number of years.
Let f(x) be the height of the tree.
a) The required function will be,
f(x) = 6x
When f(x) = 66
66 = 6x
x = 66/6
x = 11
b) Domain = 0 ≤ x ≤ 11
Range = 0 ≤ f(x) ≤ 66
c) The graph must be continuous, because the growth will not stop at only integers.
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