Domain :
The domain of a function f(x) is the set of all values for which the function is defined
Range :
The range of the function is the set of all values that f takes.
They may also have been called the input and output of the function.) .
It is like evaluating functions for the given value of x.
Example 1 :
Consider f(x) = x2 for the domain {-2, -1, 0, 1, 2}
Find the range.
Solution :
Given, f(x) = x2
If x = -2 f(-2) = (-2)2 f(-2) = 4 |
If x = -1 f(-1) = (-1)2 f(-1) = 1 |
If x = 0 f(0) = (0)2 f(0) = 0 |
If x = 1 f(1) = 12 f(1) = 1 |
If x = 2 f(2) = (2)2 f(2) = 4 |
Range = {4, 1, 0, 1, 4}
Example 2 :
For the following functions of
f : x -> f(x) on -2≤x≤2
where x ∈ z
(a) List the elements of the domain of f(x) using set notation.
(b) List the elements of the range of f(x) using set notation.
(1) f(x) = 1/(x+3)
(2) (x+3)/x and x ≠ 0
(3) f(x) = 3x
(1) Solution :
Given :
f(x) = 1/(x+3)
Domain = {-2, -1, 0, 1, 2}
f(x) = 1/(x+3) If x = -2 f(-2) = 1/(-2+3) f(-2) = 1 |
If x = -1 f(-1) = 1/(-1+3) f(-1) = 1/2 |
If x = 0 f(0) = 1/(0+3) f(0) = 1/3 |
If x = 1 f(1) = 1/(1+3) f(1) = 1/4 |
If x = 2 f(2) = 1/(2+3) f(2) = 1/5 |
Range = {1, 1/2, 1/3, 1/4, 1/5}
(2) Solution :
Given :
f(x) = (x+3)/x
Domain = {-2, -1, 0, 1, 2}
f(x) = (x+3)/x If x = -2 f(-2) = (-2+3)/(-2) f(-2) = -1/2 |
If x = -1 f(-1) = (-1+3)/(-1) f(-1) = -2 |
If x = 1 f(1) = (1+3)/1 f(1) = 4 |
If x = 2 f(2) = (2+3)/2 f(2) = 5/2 |
Range = {-1/2, -2, 5/2, 4}
(3) Solution :
Given :
f(x) = 3x
Domain = {-2, -1, 0, 1, 2}
f(x) = 3x If x = -2 f(-2) = 3-2 f(-2) = 1/32 f(-2) = 1/9 |
If x = -1 f(-1) = 3-1 f(-1) = 1/3 |
If x = 0 f(0) = 30 f(0) = 1 |
If x = 1 f(1) = 31 f(1) = 3 |
If x = 2 f(2) = 32 f(2) = 9 |
Range = {1/9, 1/3, 1, 3, 9}
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