FACTORING EXPRESSIONS

A factor is a number that is multiplied by another number to get a product. To factor is to write a number or an algebraic expression as a product.

The following steps will be useful to factor an expression.

Step 1 : 

Find the largest common divisor for all the terms in the expression given. 

Step 2 : 

Divide each term of the expression by the largest common divisor.

Step 3: 

Write the quotients inside the parentheses. 

Step 4 : 

Write the largest common divisor and the parentheses together using multiplication. 

Factor each of the following. 

Example 1 :

4x + 8

Solution : 

Find the largest common divisors for 4x and 8. 

The largest common divisor for 4x and 8 is 4. 

Divide 4x and 8 by 4

4x/4 = x

8/4 = 2

Write the quotients x and 2 inside the parentheses and multiply by the largest common divisor 4.

4(x + 2)

So, 4x + 8 = 4(x + 2).

Justify and Evaluate :

To verify our answer, let us use distributive property to multiply 4 and (x+2). 

Distribute 4 to x and 2. 

4(x + 2) = 4(x) + 4(2

4(x + 2)  =  4x + 8

When we multiply 4 and (x + 2), we get the given expression.

So, 4 and (x + 2) are the factors of 4x + 8.

Example 2 : 

Factor :

16a + 64b - 4c

Solution : 

Find the largest common divisors for 16a, 64b and 4c. 

The largest common divisor for  16a, 64b and 4c is 4. 

Divide 16a, 64b and 4c by 4 

16a/4 = 4a

64b/4 = 16b

4c/4 = c

Write the quotients 4a, 16b and c inside the parentheses and multiply by the largest common divisor 4.

4(4a + 16b - c)

So, 16a + 64b - 4c = 4(4a + 16b - c) 

Justify and Evaluate :

To verify our answer, let us use distributive property to multiply 4 and (4a + 16b - c). 

Distribute 4 to 4a, 16b and c. 

4(4a + 16b - c) = 4(4a) + 4(16b) + 4(-c)

= 16a + 64b - 4c

When we multiply 4 and (4a + 16b - c), we get the  given expression.

So, 4 and (4a + 16b - c) are the factors of 16a + 64b - 4c.

Example 3 : 

Factor :

5x2 - 15x

Solution : 

Find the largest common divisors for 5x2 and 15x. 

The largest common divisor for 5x2 and 15x is 5x. 

Divide 5x2 and 15x by 5x.

5x2/5x = x

15x/5x = 3

Write the quotients x and 3 inside the parentheses and multiply by the largest common divisor 5x.

5x(x - 3)

So, 5x2 + 15x = 5x(x - 3).

Justify and Evaluate :

To verify our answer, let us use distributive property to multiply 5x and (x - 3). 

Distribute 5x to x and 3. 

5x(x - 3) = 5x(x) - 5x(3)

5x(x - 3) = 5x2 - 15x

When we multiply 5x and (x - 3), we get the given expression.

So, 5x and (x - 3) are the factors of  5x2 - 15x.

Factoring Quadratic Expressions :

Consider the quadratic expression ax2 + bx + c.

Step 1 : 

When a = 1, find a pair of factors for 'c' such that the product of factors is equal to 'c' and sum is equal to 'b'. 

When a  1, multiply 'a' and 'c'. Now find a pair of factors for 'ac' such that the product factors is equal to 'ac' and sum is equal to 'b'. 

Step 2 : 

Split 'bx' into two terms using the factors found in step 1 and factor the expression completely. 

Example 4 :

x2 + 5x + 6

Solution : 

Find two factors of +6 such that the product is +6 and sum is +5. 

Then the two factors of +6 are +2 and +3.

Split 5x into two terms using the factors +2 and +3.

x2 + 5x + 6 = x2 + 2x + 3x + 6

= x(x + 2) + 3(x + 2)

= (x + 2)(x + 3)

Example 5 :

x2 - 15x + 56

Solution : 

Find two factors of +56 such that the product is 56 and sum is -15. 

Then the two factors of -15 are -7 and -8.

Split -15x into two terms using the factors -7 and -8.

x2 - 15x + 56 = x2 - 7x - 8x + 56

= x(x - 7) - 8(x - 7)

= (x - 7)(x - 8)

Example 6 :

x2 + 2x - 15

Solution : 

Find two factors of -15 such that the product is -15 and sum is +2. 

Then the two factors of -15 are -3 and +5.

Split -2x into two terms using the factors -3 and +5.

x2 + 2x - 15 = x2 - 3x + 5x - 15

= x(x - 3) + 5(x - 3)

= (x - 3)(x + 5)

Example 7 :

x2 - x - 20

Solution : 

Find two factors of -20 such that the product is -20 and sum is -1. 

Then the two factors of -20 are -5 and +4.

Split -x into two terms using the factors -5 and +4.

x2 - x - 20 = x2 - 5x + 4x - 20

= x(x - 5) + 4(x - 5)

= (x - 5)(x + 4)

Example 8 :

2x2 + 9x + 9

Solution : 

The product of 2 and 9 is +18.

Find two factors of +18 such that the product is +18 and sum is +9. 

Then the two factors of +18 are +3 and +6.

Split 9x into two terms using the factors +3 and +6.

2x2 + 9x + 9 = 2x2 + 3x + 6x + 9

= x(2x + 3) + 3(2x + 3)

= (2x + 3)(x + 3)

Example 9 :

3x2 + x - 4

Solution : 

The product of 3 and -4 is -12.

Find two factors of -12 such that the product is -12 and sum is +1. 

Then the two factors of -12 are -3 and +4.

Split +x into two terms using the factors -3 and +4.

3x2 + x - 4 = 3x2 - 3x + 4x - 4

= 3x(x - 1) + 4(x - 1)

= (x - 1)(3x + 4)

Factoring Expressions Using Algebraic Identities :

a2 + 2ab + b2 = (a + b)2 or (a + b)(a + b)

a2 - 2ab + b2 = (a - b)2 or (a - b)(a - b)

a2 - b2 = (a + b)(a - b)

Example 10 :

x2 + 8x + 16

Solution : 

x2 + 8x + 16 = x2 + 2(x)(4) + 42

= (x + 4)2

= (x + 4)(x + 4)

Example 11 :

x2 + 6xy + 9y2

Solution : 

x2 + 6xy + 9y= x2 + 2(x)(3y) + (3y)2

= (x + 3y)2

= (x + 3y)(x + 3y)

Example 12 :

4a2 - 20ab + 25b2

Solution : 

4a2 - 20ab + 25b2 = 22a2 - 20ab + 52b2

= (2a)2 - 20ab + (5b)2

= (2a)2 - 2(2a)(5b) + (5b)2

= (2a - 5b)2

= (2a - 5b)(2a - 5b)

Problem 13 :

9m2 - 16n2

Solution : 

9m2 - 16y2 = 32m2 - 42n2

= (3m)2 - (4n2)

= (3m + 4n)(3m - 4n)

Problem 14 :

a2b2 - c2d2

Solution : 

a2b2 - c2d2 = (ab)- (cd)2

= (ab + cd)(ab - cd)

Problem 15 :

x4 - y4

Solution : 

x4 - y= (x2)2 - (y2)2

Let a = x2 and b = y2.

= a2 - b2

= (a + b)(a - b)

Substitute a = x2 and b = y2.

= (x2 + y2)(x2 - y2)

=  (x2 + y2)(x + y)(x - y)

Factoring Cubic Expressions : 

Step 1 : 

Find the greatest common divisor (or GCD) of the two terms and the next two terms. 

Step 2 : 

Divide each of the first two terms by their GCD and the same with the next two terms. 

Step 2 : 

Write the greatest common divisors found in step 1 and results of step 2 as products and factor completely.   

Example 16 :

x3 + 3x2 + 6x + 18

Solution :

GCD of xand 3x2 is x2

Divide x3 and 3x2 by x2. The results are x and 3.

Similarly GCD of 6x and 18 is 6 

Divide 6x and 18 by 6. The results are x and 3.

x3 + 3x2 + 6x + 18 = x2(x + 3) + 6(x + 3)

= (x + 3)(x2 + 6)

Example 17 :

x3 + 2x2 - 9x - 18

Solution :

GCD of xand 2x2 is x2

Divide x3 and 2x2 by x2. The results are x and 2.

Similarly GCD of -9x and -18 is -9 

Divide -9x and -18 by -9. The results are x and 2.

x3 + 2x2 - 9x - 18 = x2(x + 2) - 9(x + 2)

= (x + 2)(x2 - 9)

= (x + 2)(x2 - 32)

= (x + 2)(x + 3)(x - 3)

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