FACTORING ALGEBRAIC EXPRESSIONS

Factoring is the process of splitting an algebraic expression into a product of simpler expressions. 

Step 1 : 

Find the greatest common divisor (or GCD) of the terms in an expression. 

Step 2 : 

Divide each term of the expression by the greatest common divisor. 

Step 2 : 

Write the greatest common divisor found in step 1 and result of step 2 as a product.  

Factor each of the following. 

Example 1 :

4x + 24y

Solution :

Greatest common divisor of 4x and 24y is 4.  

Divide 4x and 24y by 4. The results are x and 6y. 

4x + 24y = 4(x + 6y)

Example 2 :

2x2 – 8x

Solution :

GCD of 2x2 and 8x is 2x.  

Divide 2x2 and 8x by 2x. The results x and 4. 

2x2 – 8x = 2x(x - 4)

Example 3 :

x2 – 3x

Solution :

GCD of x2 and 3x is x.  

Divide x2 and 3x by x. The results x and 3. 

x2 – 3x = x(x - 3)

Example 4 :

3a + 6ab + 9a2

Solution :

GCD of 3a, 6ab and 9a2 is 1, 2b and 3a.

3a + 6ab + 9a= 3a(1 + 2b + 3a)

Example 5 :

ab + bc - 2b

Solution : 

GCD of ab, bc and 2b is b. 

Divide ab, bc and 2b by b. The results are a, c and -2.

ab + bc - 2b = b(a + c – 2)

Example 6 :

3(x – 6) + d(x – 6)

Solution :

GCD of 3(x – 6) and d(x – 6) is (x - 6). 

Divide 3(x – 6) and d(x – 6) by (x - 6). The results are 3 and d. 

3(x – 6) + d(x – 6) = (x – 6)(3 + d)

Example 7 :

2x(x + 4) + 3x + 12

Solution :

In the expression above, GCD of 3x and 12 is 3. 

Divide 3x and 12 by 3. The results are x and 4.

2x(x + 4) + 3x + 12 = 2x(x + 4) + 3(x + 4)

GCD of 2x(x + 4) and 3(x + 4) is (x + 4). 

Divide 2x(x + 4) and 3(x + 4) by (x + 4). The results are 2x and 3.

2x(x + 4) + 3x + 12 = (x + 4)(2x + 3)

Example 8 :

4x2y3 + 6x3y2

Solution :

GCD of 4x2y3 + 6x3yis 2x2y2

Divide 4x2y3 and 6x3y2 is 2x2y2. The results are 2y and 3x.

4x2y3 + 6x3y2 = 2xy(2x + 3y)

Factoring Quadratic Expressions :

Consider the quadratic expression ax2 + bx + c.

Step 1 : 

When a = 1, find a pair of factors for 'c' such that the product of factors is equal to 'c' and sum is equal to 'b'. 

When a  1, multiply 'a' and 'c'. Now find a pair of factors for 'ac' such that the product factors is equal to 'ac' and sum is equal to 'b'. 

Step 2 : 

Split 'bx' into two terms using the factors found in step 1 and factor the expression completely. 

Example 9 :

x2 + 5x + 6

Solution : 

Find two factors of +6 such that the product is +6 and sum is +5. 

Then the two factors of +6 are +2 and +3.

Split 5x into two terms using the factors +2 and +3.

x2 + 5x + 6 = x2 + 2x + 3x + 6

= x(x + 2) + 3(x + 2)

= (x + 2)(x + 3)

Example 10 :

x2 - 15x + 56

Solution : 

Find two factors of +56 such that the product is 56 and sum is -15. 

Then the two factors of -15 are -7 and -8.

Split -15x into two terms using the factors -7 and -8.

x2 - 15x + 56 = x2 - 7x - 8x + 56

= x(x - 7) - 8(x - 7)

= (x - 7)(x - 8)

Example 11 :

x2 + 2x - 15

Solution : 

Find two factors of -15 such that the product is -15 and sum is +2. 

Then the two factors of -15 are -3 and +5.

Split -2x into two terms using the factors -3 and +5.

x2 + 2x - 15 = x2 - 3x + 5x - 15

= x(x - 3) + 5(x - 3)

= (x - 3)(x + 5)

Example 12 :

x2 - x - 20

Solution : 

Find two factors of -20 such that the product is -20 and sum is -1. 

Then the two factors of -20 are -5 and +4.

Split -x into two terms using the factors -5 and +4.

x2 - x - 20 = x2 - 5x + 4x - 20

= x(x - 5) + 4(x - 5)

= (x - 5)(x + 4)

Example 13 :

2x2 + 9x + 9

Solution : 

The product of 2 and 9 is +18.

Find two factors of +18 such that the product is +18 and sum is +9. 

Then the two factors of +18 are +3 and +6.

Split 9x into two terms using the factors +3 and +6.

2x2 + 9x + 9 = 2x2 + 3x + 6x + 9

= x(2x + 3) + 3(2x + 3)

= (2x + 3)(x + 3)

Example 14 :

3x2 + x - 4

Solution : 

The product of 3 and -4 is -12.

Find two factors of -12 such that the product is -12 and sum is +1. 

Then the two factors of -12 are -3 and +4.

Split +x into two terms using the factors -3 and +4.

3x2 + x - 4 = 3x2 - 3x + 4x - 4

= 3x(x - 1) + 4(x - 1)

= (x - 1)(3x + 4)

Factoring Expressions Using Algebraic Identities :

a2 + 2ab + b2 = (a + b)2 or (a + b)(a + b)

a2 - 2ab + b2 = (a - b)2 or (a - b)(a - b)

a2 - b2 = (a + b)(a - b)

Example 15 :

x2 + 8x + 16

Solution : 

x2 + 8x + 16 = x2 + 2(x)(4) + 42

= (x + 4)2

= (x + 4)(x + 4)

Example 16 :

x2 + 6xy + 9y2

Solution : 

x2 + 6xy + 9y= x2 + 2(x)(3y) + (3y)2

= (x + 3y)2

= (x + 3y)(x + 3y)

Example 17 :

4a2 - 20ab + 25b2

Solution : 

4a2 - 20ab + 25b2 = 22a2 - 20ab + 52b2

= (2a)2 - 20ab + (5b)2

= (2a)2 - 2(2a)(5b) + (5b)2

= (2a - 5b)2

= (2a - 5b)(2a - 5b)

Problem 18 :

9m2 - 16n2

Solution : 

9m2 - 16y2 = 32m2 - 42n2

= (3m)2 - (4n2)

= (3m + 4n)(3m - 4n)

Problem 19 :

a2b2 - c2d2

Solution : 

a2b2 - c2d2 = (ab)- (cd)2

= (ab + cd)(ab - cd)

Problem 20 :

x4 - y4

Solution : 

x4 - y= (x2)2 - (y2)2

Let a = x2 and b = y2.

= a2 - b2

= (a + b)(a - b)

Substitute a = x2 and b = y2.

= (x2 + y2)(x2 - y2)

=  (x2 + y2)(x + y)(x - y)

Factoring Cubic Expressions : 

Step 1 : 

Find the greatest common divisor (or GCD) of the two terms and the next two terms. 

Step 2 : 

Divide each of the first two terms by their GCD and the same with the next two terms. 

Step 2 : 

Write the greatest common divisors found in step 1 and results of step 2 as products and factor completely.   

Example 21 :

x3 + 3x2 + 6x + 18

Solution :

GCD of xand 3x2 is x2

Divide x3 and 3x2 by x2. The results are x and 3.

Similarly GCD of 6x and 18 is 6 

Divide 6x and 18 by 6. The results are x and 3.

x3 + 3x2 + 6x + 18 = x2(x + 3) + 6(x + 3)

= (x + 3)(x2 + 6)

Example 22 :

x3 + 2x2 - 9x - 18

Solution :

GCD of xand 2x2 is x2

Divide x3 and 2x2 by x2. The results are x and 2.

Similarly GCD of -9x and -18 is -9 

Divide -9x and -18 by -9. The results are x and 2.

x3 + 2x2 - 9x - 18 = x2(x + 2) - 9(x + 2)

= (x + 2)(x2 - 9)

= (x + 2)(x2 - 32)

= (x + 2)(x + 3)(x - 3)

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