Problem 1
Evaluate :
-82
Problem 2 :
Evaluate :
(-8)2
Problem 3 :
Evaluate :
(-8)3
Problem 4 :
Evaluate :
3-2
Problem 5 :
Evaluate :
(-3/2)-2
Problem 6 :
Evaluate :
(-5/4)-3
Problem 7 :
Evaluate :
(-5-2) ⋅ (-3-4)
Problem 8 :
Evaluate :
(-3)-4/ (-2)-3
Problem 9 :
It is given that -a-1/3 = 3. Find the value of a.
Problem 10 :
It is given that (-a)-1/3 = 4/3. Find the value of a.
Problem 11 :
Express (153)–16 as a single exponent of 15.
Problem 12 :
By what number should (7)–2 be multiplied so that the product may be equal to (-343)-1?
Problem 13 :
By what number should (−3/4)5 be multiplied so that the product may be equal to (−64/27)-1 ?
Problem 14 :
(-7/11)-3 x (-7/11)5x = [(-7/11)-2]-1
Problem 15 :
(3/7)-2x + 1 ÷ (3/7)-1 = [(3/7)-1]-7
Problem 16 :
(-4/5)3 x 52 x (-1/2)5 x (1/2)-3
Problem 17 :
The value of the expression (1/3)3 x (-2/5)2 x (-3/2)3
Problem 18 :
The value of the expression (-1/4)-3 x (-1/4)-2
Problem 19 :
Find m so that (–3)m +1 × (–3)5 = (–3)7
Problem 20 :
If 3x + y = 81 and 81x- y = 3, then find the values of x and y
Problem 1 :
Evaluate :
-82
Solution :
= -82
= - 8 ⋅ 8
= - 64
Problem 2 :
Evaluate :
(-8)2
Solution :
= (-8)(-8)
= 64
Problem 3 :
Evaluate :
(-8)3
Solution :
= (-8)(-8)(-8)
= -512
Problem 4 :
Evaluate :
3-2
Solution :
= 3-2
= (1/3)2
Distribute the exponent to numerator and denominator.
= 12 / 32
= 1/9
Problem 5 :
Evaluate :
(-3/2)-2
Solution :
= (-3/2)-2
= (-2/3)2
Since the exponent is even, the negative sign inside the parentheses will become positive.
= (2/3)2
Distribute the exponent to numerator and denominator.
= 22/32
= 4/9
Problem 6 :
Evaluate :
(-5/4)-3
Solution :
= (-5/4)-3
= (-4/5)3
Since the exponent is odd, the negative sign inside the parentheses will remain same.
Distribute the exponent to numerator and denominator.
= -43/53
= -64/125
Problem 7 :
Evaluate :
(-5-2) ⋅ (-3-4)
Solution :
= (-5-2) ⋅ (-3-4)
= (-1/5)2 ⋅ (-1/3)4
= (1/25) ⋅ (1/81)
= 1/2025
Problem 8 :
Evaluate :
(-3)-4/(-2)-3
Solution :
= (-3)-4/(-2)-3
= (-1/3)4/(-1/2)3
= (1/81)/(-1/8)
= (1/81) ⋅ (-8/1)
= -8/81
Problem 9 :
It is given that -a-1/3 = 3. Find the value of a.
Solution :
-a1/3 = 3
Multiply each side by -1.
a1/3 = -3
a = (-3)3/1
= (-3)3
= (-3)(-3)(-3)
= -27
Problem 10 :
It is given that (-a)-1/3 = 4/3. Find the value of a.
Solution :
(-a)-1/3 = 4/3
-a = (4/3)-3/1
-a = (4/3)-3
-a = (3/4)3
Distribute the exponent to numerator and denominator.
-a = 33/43
-a = 27/64
Multiply each side by -1.
a = - 27/64
Problem 11 :
Express (153)–16 as a single exponent of 15.
Solution :
= (153)–16
Since we have power raised by another power, we can multiply the powers.
= 153(–16)
= 15–48
= (1/15)48
Problem 12 :
By what number should (7)–2 be multiplied so that the product may be equal to (-343)-1?
Solution :
Let x be the required number to be multiplied.
(7)–2 ⋅ x = (-343)-1
Converting the negative exponents as positive exponents, we get
343 = 7 ⋅ 7 ⋅ 7
= 73
(1/72) ⋅ x = (-73)-1
(1/72) ⋅ x = (-7)-3
(1/72) ⋅ x = (-1/73)
x = (-1/73) ⋅ (72/1)
x = -1/7
Problem 13 :
By what number should (−3/4)5 be multiplied so that the product may be equal to (−64/27)-1 ?
Solution :
Let x be the required number.
(−3/4)5 ⋅ x = (−64/27)-1
(−3/4)5 ⋅ x = (−27/64)
x = (−27/64)(−4/3)5
x = (−33/43)(−45/35)
= 42 / 32
= 16/9
Problem 14 :
(-7/11)-3 x (-7/11)5x = [(-7/11)-2]-1
Solution :
(-7/11)-3 x (-7/11)5x = [(-7/11)-2]-1
(-7/11)-3+5x = (-7/11)2
-3 + 5x = 2
5x = 2 + 3
5x = 5
x = 5/5
x = 1
Problem 15 :
(3/7)-2x + 1 ÷ (3/7)-1 = [(3/7)-1]-7
Solution :
(3/7)-2x + 1 ÷ (3/7)-1 = [(3/7)-1]-7
(3/7)-2x + 1 x (3/7)1 = (3/7)7
(3/7)-2x + 1 + 1 = (3/7)7
(3/7)-2x + 2 = (3/7)7
Since the bases are equal, by equating the powers, we get
-2x + 2 = 7
-2x = 7 - 2
-2x = 5
x = -5/2
Problem 16 :
(-4/5)3 x 52 x (-1/2)5 x (1/2)-3
Solution :
= (-4/5)3 x 52 x (-1/2)5 x (1/2)-3
= (-64/125) x 25 x (-1/32) x (2)3
= (-64/5) x (-1/32) x 8
= 16/5
Problem 17 :
The value of the expression (1/3)3 x (-2/5)2 x (-3/2)3
Solution :
= (1/3)3 x (-2/5)2 x (-3/2)3
Using the exponents, we get
= (1/27) x (4/25) x (-27/8)
= 1/50
Problem 18 :
The value of the expression (-1/4)-3 x (-1/4)-2
Solution :
= (-1/4)-3 x (-1/4)-2
To convert the negative exponents as positive exponent, we have to write each fractions as its reciprocal
= (-4)3 x (-4)2
= -64 x 16
= -1024
Problem 19 :
Find m so that (–3)m +1 × (–3)5 = (–3)7
Solution :
(–3)m +1 × (–3)5 = (–3)7
(–3)m + 1 + 5 = (–3)7
(–3)m + 6 = (–3)7
Equating the powers, we get
m + 6 = 7
m = 7 - 6
m = 1
So, the value of m is 1.
Problem 20 :
If 3x + y = 81 and 81x- y = 3, then find the values of x and y
Solution :
3x + y = 81 and 81x- y = 3
3x + y = 34 and 34(x - y) = 3
x + y = 4 -----(1)
4(x - y) = 3 -----(2)
From (1), y = 4 - x
4(x - (4 - x)) = 3
4(x - 4 + x) = 3
4(2x - 4) = 3
2x - 4 = 3/4
2x = (3/4) + 4
2x = 19/4
x = 19/8
So, the value of x is 19/8
y = 4 - (19/8)
y = (32 - 19)/8
= 13/8
So, the value of y is 13/8
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