Problem 1 :
Find x so that
(-5)x+1 ⋅ (-5)5 = (-5)7
Problem 2 :
(5/3)-2 ⋅ (5/3)-14 = (5/3)8x
Problem 3 :
Find x so that
(-2)3 ⋅ (-2)-6 = (-2)2x-1
Problem 4 :
Simplify
30+31-3-1
Problem 5 :
Simplify
(-125)1/3
Problem 6 :
Simplify
(32)2/5
Problem 7 :
Simplify
(64)5/6
Problem 8 :
Simplify
(81)-3/4
Problem 9 :
Simplify
3pq-1
Problem 10 :
Simplify
(3x ⋅ 9x)/(27)x+2
Problem 11 :
Simplify
2x ⋅ 8
Problem 12 :
Simplify
5n+2/5n-2
Problem 13 :
Simplify
51+x/5x-1
Problem 14 :
Simplify
8x/16y
Problem 15 :
Simplify
(5t-2)-1
Problem 16 :
Simplify
(xy)3/y-2
Problem 17 :
Simplify
3x-2 = 1/9
Problem 17 :
Simplify
3x-2 = 1/9
Problem 1 :
Find x so that
(-5)x+1 ⋅ (-5)5 = (-5)7
Solution :
(-5)x+1 ⋅ (-5)5 = (-5)7
Using the rule of exponent am ⋅ an = am+n
(-5) x+1+5 = (-5)7
When bases are equal on both sides, we can equate the powers.
(-5) x+6 = (-5)7
x+6 = 7
x = 7 - 6
x = 1
So, the value of x is 1.
Problem 2 :
(5/3)-2 ⋅ (5/3)-14 = (5/3)8x
Solution :
(5/3)-2 ⋅ (5/3)-14 = (5/3)8x
Using the rule of exponent am ⋅ an = am+n
(5/3)-2-14 = (5/3)8x
(5/3)-16 = (5/3)8x
When bases are equal on both sides, we can equate the powers.
-16 = 8x
x = -16/8
x = -2
So, the value of x is -2.
Problem 3 :
Find x so that
(-2)3 ⋅ (-2)-6 = (-2)2x-1
Solution :
(-2)3 ⋅ (-2)-6 = (-2)2x-1
Using the rule of exponent am ⋅ an = am+n
(-2)3-6 = (-2)2x-1
(-2)-3 = (-2)2x-1
By equating the powers, we can solve for the variable.
2x-1 = -3
2x = -3+1
2x = -2
x = -1
So, the value of x is -1.
Problem 4 :
Simplify
30+31-3-1
Solution :
30+31-3-1
Anything to the power 0 is 1. To convert the negative exponent as positive, we have to convert it as it
= 1 + 3 - (1/3)
= 4 - (1/3)
= (12-1)/3
= 11/3
The answer is 11/3.
Problem 5 :
Simplify
(-125)1/3
Solution :
(-125)1/3
Writing 125 is exponential form, we get
-125 = -5⋅(-5)⋅(-5) ==> (-5)3
= [(-5)3]1/3
Using the property (am)n = amn. When we have power raised by another power, we have to multiply the powers.
= -5
The answer is -5.
Problem 6 :
Simplify
(32)2/5
Solution :
(32)2/5
Writing 32 in exponential form, we get
32 = 2⋅2⋅2⋅2⋅2 ==> 25
= (25)2/5
If we have power raised by another power, we will multiply these two powers. Then 5 x 25 will give 2.
= 22
= 4
The answer is 4.
Problem 7 :
Simplify
(64)5/6
Solution :
(64)5/6
Writing 64 in exponential form, we get
64 = 2⋅2⋅2⋅2⋅2⋅2 ==> 26
= (26)5/6
When we have power raised by another power, we have to multiply both powers.
= 25
= 32
The answer is 32.
Problem 8 :
Simplify
(81)-3/4
Solution :
(81)-3/4
Writing 81 in exponential form, we get
81 = 3⋅3⋅3⋅3 ==> 34
= (34)-3/4
Power raised by another power here. So, we have to multiply the powers.
= 3-3
By writing the reciprocal of 3-3, we can convert the negative exponent as positive.
= 1/33
= 1/27
The answer is 1/27.
Problem 9 :
Simplify
3pq-1
Solution :
The variable q is having negative exponent, by changing the negative exponent as positive exponent, we get
3pq-1 = 3p/q
The answer is 3p/q.
Problem 10 :
Simplify
(3x ⋅ 9x)/(27)x+2
Solution :
(3x ⋅ 9x)/(27)x+2
We write 9 in exponential form, then 9 = 32
= (3x ⋅ 32x)/(33)x+2
= (3x+2x)/33(x+2)
= 3x+2x/33x+6
= 3(3x-3x-6)
= 3-6
= 1/36
The answer is 1/36.
Problem 11 :
Simplify
2x ⋅ 8
Solution :
2x ⋅ 8
= 2x ⋅ 23
= 2(x+3)
The answer is 2(x+3).
Problem 12 :
Simplify
5n+2/5n-2
Solution :
= 5n+2/5n-2
= 5(n+2)-(n-2)
= 5n+2-n+2
= 54
The answer is 54 or 625.
Problem 13 :
Simplify
51+x/5x-1
Solution :
= 51+x/5x-1
= 5(1+x)-(1+x)
= 51+x-1-x
= 52
So, the answer is 25.
Problem 14 :
Simplify
8x/16y
Solution :
= 8x/16y
8 = 23 and 16 = 24
= 23x/24y
= 23x-4y
Problem 15 :
Simplify
(5t-2)-1
Solution :
= (5t-2)-1
= 1/5t-2
= t2/5
Problem 16 :
Simplify
(xy)3/y-2
Solution :
= (xy)3/y-2
= x3y3/y-2
= x3y3⋅ y2
= x3y5
Problem 17 :
Simplify
3x-2 = 1/9
Solution :
3x-2 = 1/32
3x-2 = 1⋅3-2
3x-2 = 3-2
x-2 = -2
x = -2+2
x = 0
Problem 18 :
If (25)150 = (25x)50, then the value of x will be
a) 53 b) 54 c) 52 d) 5
Solution :
(25)150 = (25x)50
Since two terms are multiplied, distributing the power. We get
(25)150 = (25)50 x50
(25)150 / (25)50 = x50
25150-50 = x50
25100 = x50
(252)50 = x50
x = 252
Writing 25 in exponential form, we get
x = (52)2
x = 54
So, option b is the answer.
Problem 19 :
Find the value of a from the following :
(√9)-5 x (√3)-7 = (√3)-a
a) 11 b) 13 c) 15 d) 17
Solution :
(√9)-5 x (√3)-7 = (√3)-a
(√(3)2)-5 x (√3)-7 = (√3)-a
(3)-5 x (3)-7/2 = (3)-a/2
(3)-5-(7/2) = (3)-a/2
By equating the power, we get
-5 - (7/2) = -a/2
-17/2 = -a/2
a = 17
So, the value of a is 17.
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