EXPONENTS AND POWERS PRACTICE QUESTIONS

Problem 1 :

Find x so that

(-5)x+1 ⋅ (-5)5  =  (-5)7

Problem 2 :

(5/3)-2 ⋅ (5/3)-14  =  (5/3)8x

Problem 3 :

Find x so that

(-2)⋅ (-2)-6  =  (-2)2x-1

Problem 4 :

Simplify

30+31-3-1

Problem 5 :

Simplify

(-125)1/3

Problem 6 :

Simplify

(32)2/5

Problem 7 :

Simplify

(64)5/6

Problem 8 :

Simplify

(81)-3/4

Problem 9 :

Simplify

3pq-1

Problem 10 :

Simplify

(3x ⋅ 9x)/(27)x+2 

Problem 11 :

Simplify

2x ⋅ 8

Problem 12 :

Simplify

5n+2/5n-2

Problem 13 :

Simplify

51+x/5x-1

Problem 14 :

Simplify

8x/16y

Problem 15 :

Simplify

(5t-2)-1

Problem 16 :

Simplify

(xy)3/y-2

Problem 17 :

Simplify

3x-2  =  1/9

Problem 17 :

Simplify

3x-2  =  1/9

Detailed Solution

Problem 1 :

Find x so that

(-5)x+1 ⋅ (-5)5  =  (-5)7

Solution :

(-5)x+1 ⋅ (-5)5  =  (-5)7

Using the rule of exponent am ⋅ an = am+n

(-5) x+1+5  =  (-5)7

When bases are equal on both sides, we can equate the powers.

(-5) x+6  =  (-5)7

x+6  =  7

x  =  7 - 6

x  =  1

So, the value of x is 1.

Problem 2 :

(5/3)-2 ⋅ (5/3)-14  =  (5/3)8x

Solution :

(5/3)-2 ⋅ (5/3)-14  =  (5/3)8x

Using the rule of exponent am ⋅ an = am+n

(5/3)-2-14  =  (5/3)8x

(5/3)-16  =  (5/3)8x

When bases are equal on both sides, we can equate the powers.

-16  =  8x

x  =  -16/8

x  =  -2

So, the value of x is -2.

Problem 3 :

Find x so that

(-2)⋅ (-2)-6  =  (-2)2x-1

Solution :

(-2)⋅ (-2)-6  =  (-2)2x-1

Using the rule of exponent am ⋅ an = am+n

(-2)3-6  =  (-2)2x-1

(-2)-3  =  (-2)2x-1

By equating the powers, we can solve for the variable.

2x-1  =  -3

2x  =  -3+1

2x  =  -2

x  =  -1

So, the value of x is -1.

Problem 4 :

Simplify

30+31-3-1

Solution :

30+31-3-1

Anything to the power 0 is 1. To convert the negative exponent as positive, we have to convert it as it


=  1 + 3 - (1/3)

=  4 - (1/3)

=  (12-1)/3

=  11/3

The answer is 11/3.

Problem 5 :

Simplify

(-125)1/3

Solution :

(-125)1/3

Writing 125 is exponential form, we get

-125  =  -5⋅(-5)⋅(-5)  ==>  (-5)3

=  [(-5)3]1/3

Using the property (am)n = amn. When we have power raised by another power, we have to multiply the powers.

=  -5

The answer is -5.

Problem 6 :

Simplify

(32)2/5

Solution :

(32)2/5

Writing 32 in exponential form, we get

32  =  2⋅2⋅2⋅2⋅2 ==>  25

=  (25)2/5

If we have power raised by another power, we will multiply these two powers. Then 5 x 25 will give 2.

=  22

=  4

The answer is 4.

Problem 7 :

Simplify

(64)5/6

Solution :

(64)5/6

Writing 64 in exponential form, we get

64  =  2⋅2⋅2⋅2⋅2⋅2 ==>  26

=  (26)5/6

When we have power raised by another power, we have to multiply both powers.

=  25

=  32

The answer is 32.

Problem 8 :

Simplify

(81)-3/4

Solution :

(81)-3/4

Writing 81 in exponential form, we get

81  =  3⋅3⋅3⋅3 ==>  34

=  (34)-3/4

Power raised by another power here. So, we have to multiply the powers.

=  3-3

By writing the reciprocal of 3-3, we can convert the negative exponent as positive.

=  1/33

=  1/27

The answer is 1/27.

Problem 9 :

Simplify

3pq-1

Solution :

The variable q is having negative exponent, by changing the negative exponent as positive exponent, we get

3pq-1  =  3p/q

The answer is 3p/q.

Problem 10 :

Simplify

(3x ⋅ 9x)/(27)x+2 

Solution :

(3x ⋅ 9x)/(27)x+2

We write 9 in exponential form, then 9 = 32

=  (3x ⋅ 32x)/(33)x+2 

=  (3x+2x)/33(x+2) 

=  3x+2x/33x+6 

=  3(3x-3x-6)

=  3-6

=  1/36

The answer is 1/36.

Problem 11 :

Simplify

2x ⋅ 8

Solution :

2x ⋅ 8

=  2x ⋅ 23

=  2(x+3)

The answer is 2(x+3).

Problem 12 :

Simplify

5n+2/5n-2

Solution :

=  5n+2/5n-2

=  5(n+2)-(n-2)

=  5n+2-n+2

=  54

The answer is 54 or 625.

Problem 13 :

Simplify

51+x/5x-1

Solution :

=  51+x/5x-1

=  5(1+x)-(1+x)

=  51+x-1-x

=  52

So, the answer is 25.

Problem 14 :

Simplify

8x/16y

Solution :

=  8x/16y

8  =  23 and 16  =  24

=  23x/24y

=  23x-4y

Problem 15 :

Simplify

(5t-2)-1

Solution :

=  (5t-2)-1

=  1/5t-2

=  t2/5

Problem 16 :

Simplify

(xy)3/y-2

Solution :

=  (xy)3/y-2

=  x3y3/y-2

=  x3y3⋅ y2

=  x3y5

Problem 17 :

Simplify

3x-2  =  1/9

Solution :

3x-2  =  1/32

3x-2  =  13-2

3x-2  =  3-2

x-2  =  -2

x  =  -2+2

x  =  0

Problem 18 :

If (25)150 = (25x)50, then the value of x will be

a) 53    b)  54     c)  52     d)  5

Solution :

(25)150 = (25x)50

Since two terms are multiplied, distributing the power. We get

(25)150 = (25)50 x50

(25)150 / (25)50 = x50

25150-50 = x50

25100 = x50

(252)50 = x50

x = 252

Writing 25 in exponential form, we get

x = (52)2

x = 54

So, option b is the answer.

Problem 19 :

Find the value of a from the following :

(√9)-5 x (√3)-7 = (√3)-a

a)  11   b)  13   c)  15    d)  17

Solution :

(√9)-5 x (√3)-7 = (√3)-a

(√(3)2)-5 x (√3)-7 = (√3)-a

(3)-5 x (3)-7/2 = (3)-a/2

(3)-5-(7/2) = (3)-a/2

By equating the power, we get

-5 - (7/2) = -a/2

-17/2 = -a/2

a = 17

So, the value of a is 17.

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