EVALUATING EXPRESSIONS WITH EXPONENTS WORKSHEET

Problem 1 :

Evaluate :

(-1)4

Problem 2 :

Evaluate :

(-1)5

Problem 3 :

Evaluate :

-(-3)3

Problem 4 :

Evaluate :

50

Problem 5 :

Evaluate :

-30

Problem 6 :

Evaluate :

(-7)0

Problem 7 :

Evaluate :

5-3

Problem 8 :

Evaluate :

23 ⋅ 3⋅ (-1)5

Problem 9 :

Evaluate :

(-1)4 ⋅ 3⋅ 22

Problem 10 :

If x2y3 = 10 and x3y2 = 8, then find the value of x5y5.

1. Answer :

(-1)4

Order of operations (PEMDAS) dictates that parentheses take precedence.

Here, the exponent 4 is an even number. So, the negative sign inside the parentheses will become positive.

When 1 is multiplied by itself any number of times, the result will be 1.

More clearly,

(-1)= (-1) ⋅ (-1) (-1) ⋅ (-1)

(-1)= 1

2. Answer :

(-1)5

Order of operations (PEMDAS) dictates that parentheses take precedence.

Here, the exponent 5 is an odd number. So, the negative sign inside the parentheses will remain same.

When 1 is multiplied by itself any number of times, the result will be 1.

More clearly,

(-1)= (-1) ⋅ (-1) ⋅ (-1) ⋅ (-1) ⋅ (-1)

(-1)= -1

3. Answer :

-(-3)3

Order of operations (PEMDAS) dictates that parentheses take precedence.

-[(-3)3] = -[(-3) ⋅ (-3) ⋅ (-3)]

-[(-3)3] = -[-27]

-[(-3)3] = 27

4. Answer :

50

Anything to the power zero is equal to 1.

So, we have

50 = 1

5. Answer :

-30

Anything to the power zero is equal to 1.

So, we have

-30 = -1

6. Answer :

(-7)0

Order of operations (PEMDAS) dictates that parentheses take precedence.

Anything to the power zero is equal to 1.

So, we have

(-7)0 = 1

7. Answer :

5-3

Using laws of exponents, we have

5-3 = 1/53

5-3 = 1/125

8. Answer :

23 ⋅ 3⋅ (-1)5

In the above expression, first evaluate each term separately. 

23 = 2 ⋅ 2 ⋅ 2 = 8

32 = 3 ⋅ 3 = 9

(-1)= (-1) ⋅ (-1) ⋅ (-1) ⋅ (-1) ⋅ (-1) = -1

Now, we have

23 ⋅ 3⋅ (-1)5 = 8 ⋅ 9 ⋅ (-1)

23 ⋅ 3⋅ (-1)5 = -72

9. Answer :

In the above expression, first evaluate each term separately.

(-1)= (-1) ⋅ (-1) ⋅ (-1) ⋅ (-1) = 1

33 = 3 ⋅ 3 ⋅ 3 = 27

22 = 2 ⋅ 2 = 4

Now, we have

(-1)4 ⋅ 3⋅ 2= 1 ⋅ 27 ⋅ 4

(-1)4 ⋅ 3⋅ 2= 108

10. Answer :

x2y3 = 10 ----(1)

x3y2 = 8 ----(2)

Multiply (1) and (2) :

(1) ⋅ (2) ----> (x2y3) ⋅ (x3y2) = 10 ⋅ 8

x5y5 = 80

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