EVALUATE EACH FUNCTION FOR THE GIVEN INPUT VALUES

Find the value of y given rule :

Example 1  :

y  =  8x+5

when (i) x  =  3 (ii) x  =  7 (iii) x  =  10 1/2

Solution :

Given rule, y  =  8x+5

(i) when x  =  3

By applying x  =  3 in given rule, we get

y  =  8x+5

y  =  8(3)+5

y  =  24+5

y  =  29

Therefore, the value of y is 29

(ii) x  =  7

By applying x  =  7 in given rule, we get

y  =  8x+5

y  =  8(7)+5

y  =  56+5

y  =  61

Therefore, the value of y is 61

(iii) x  =  10 1/2

Since the value of x is mixed fraction, we convert it into improper. 

10 1/2  =  13/2

By applying x  =  13/2 in given rule, we get

y  =  8x+5

y  =  8(13/2)+5

y  =  52+5

y  =  57

Therefore, the value of y is 57

Example 2 :

y  =  21-4x

when (i) x  =  0 (ii) x  =  2 1/2 (iii) x  =  7

Solution :

Given rule, y  =  21-4x

(i) x  =  0

By applying x  =  0 in given rule, we get

y  =  21-4x

y  =  21-4(0)

y  =  21

Therefore, the value of y is 21

(ii) x  =  2 1/2

Converting the mixed fraction into improper fraction,

2 1/2  =  5/2

By applying x  =  5/2 in given rule, we get

y  =  21-4x

y  =  21-4(5/2)

y  =  21-10

y  =  11

Therefore, the value of y is 11

(iii) x  =  7

By applying x  =  7 in given rule, we get

y  =  21-4x

y  =  21-4(7)

y  =  21-28

y  =  -7

Therefore, the value of y is -7

Example 3 :

y  =  (3x+4)/2

when (i) x  =  2 (ii) x  =  6 (iii) x  =  11

Solution :

Given rule, y  =  (3x+4)/2

(i) x  =  2

By applying x  =  2 in given rule, we get

y  =  (3x+4)/2

y  =  [3(2)+4]/2

y  =  (6+4)/2

y  =  (10/2)

y  =  5

Therefore, the value of y is 5

(ii) x  =  6

By applying x  =  6 in given rule, we get

y  =  (3x+4)/2

y  =  [3(6)+4]/2

y  =  (18+4)/2

y  =  (22/2)

y  =  11

Therefore, the value of y is 11

(iii) x  =  11

By applying x  =  11 in given rule, we get

y  =  (3x+4)/2

y  =  [3(11)+4]/2

y  =  (33+4)/2

y  =  (37/2)

y  =  18.5

Therefore, the value of y is 18.5

Example 4 :

y  =  2(x+3)-1

when (i) x  =  4 (ii) x  =  0 (iii) x  =  6 1/2

Solution :

Given rule, y  =  2(x+3)-1

(i) x  =  4

By applying x  =  4 in given rule, we get

y  =  2(x+3)-1

y  =  2(4+3)-1

y  =  2(7)-1

y  =  14-1

y  =  13

Therefore, the value of y is 13

(ii) x  =  0

By applying x  =  0 in given rule, we get

y  =  2(x+3)-1

y  =  2(0+3)-1

y  =  2(3)-1

y  =  6-1

y  =  5

Therefore, the value of y is 5

(iii) x  =  6 1/2

Changing into mixed fraction, we get

6 1/2  =  13/2

By applying x  =  13/2 in given rule, we get

y  =  2(x+3)-1

y  =  2(13/2+3)-1

y  =  2(19/2)-1

y  =  19-1

y  =  18

Therefore, the value of y is 18.

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