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The fractions which are equivalent have the same value, even though they may look different. These fractions are really the same.
For example,
ΒΎ = βΆββ = βΉβββ
Why are they the same ?
Because, when we multiply or divide both the numerator and denominator by the same number, the fraction keeps it's value.
Let us divide a rectangle into two equal parts and shade one of the parts.

In the above rectangle, the shaded part is Β½.
That is, in total of 2 parts, one part is shaded.
Let us divide the same rectangle into four equal parts and shade 2 parts.

In the above rectangle, the shaded part is Β²ββ.
That is, in total of 4 parts, two parts are shaded.
Let us divide the same rectangle into six equal parts and shade 3 parts.

In the above rectangle, the shaded part is Β³ββ.
That is, in total of 6 parts, three parts are shaded.
In all the above figures, the shaded portion are equal but they can be represented by different fractions.
Β½ = Β²ββ = Β³ββ
When two or more fractions represent the same part of a whole, the fractions are called equivalent.
Change both numerator and denominator using multiplication or division by the same number.
Example :
Using multiplication :

Β½, Β²ββ and β΄ββ are equivalent fractions.
Using division :

ΒΉβΈβββ, βΆβββ and Β½ are equivalent fractions.
Problem 1 :
Write 4 fractions which are equivalent to β .
Solution :
To find 4 fractions which are equivalent to β , multiply both numerator and denominator of the fraction β by 2, 3, 4 and 5.
β = β½β΅Λ£Β²βΎββββββ = ΒΉβ°βββ
β
= β½β΅Λ£Β³βΎββββββ = ΒΉβ΅βββ
β
= β½β΅Λ£β΄βΎββββββ = Β²β°βββ
β = β½β΅Λ£β΅βΎβββββ β = Β²β΅βββ
The four fractions which are equivalent to β are
ΒΉβ°βββ, ΒΉβ΅βββ, Β²β°βββ and Β²β΅βββ
Problem 2 :
Write 3 fractions which are equivalent to Β³ββ.
Solution :
Β³ββ = β½Β³Λ£Β²βΎββββββ = βΆβββ
Β³ββ = β½Β³Λ£Β³βΎββββββ = βΉβββ
Β³ββ = β½Β³Λ£β΄βΎββββββ = ΒΉΒ²βββ
The four fractions which are equivalent to Β³ββ are
βΆβββ, βΉβββ and ΒΉΒ²βββ
Problem 3 :
Write 4 fractions which are equivalent to 0.03.
Solution :
Write 0.03 as as a fraction.
0.03 = Β³ββββ
To find 4 fractions which are equivalent to Β³ββββ, multiply both numerator and denominator of the fraction Β³ββββ by 2, 3, 4 and 5.
Β³ββββ = β½Β³Λ£Β²βΎββββββββ = βΆββββ
Β³ββββ = β½Β³Λ£Β³βΎββββββββ = βΉββββ
Β³ββββ = β½Β³Λ£β΄βΎββββββββ = ΒΉΒ²ββββ
Β³ββββ = β½Β³Λ£β΅βΎβββββββ β = ΒΉβ΅ββ ββ
The four fractions which are equivalent to Β³ββ are
βΆββββ, βΉββββ, ΒΉΒ²ββββ and ΒΉβ΅ββ ββ
Problem 4 :
Pick out the fractions which are equivalent :
β , ΒΉΒ²βββ, β , β΅βββ , ΒΉβΆβββ, ΒΎ, βΉβββ
Solution :
The fractions β and ΒΉβΆβββ are equivalent.
Because,
β = β½Β²Λ£βΈβΎβββ βββ = ΒΉβΆβββ
The fractions ΒΉΒ²βββ, ΒΎ and βΉβββ are equivalent.
Because,
ΒΉΒ²βββ = β½ΒΉΒ²Γ·β΄βΎββββΓ·ββ = ΒΎ
and
βΉβββ = β½βΉΓ·Β³βΎββββΓ·ββ = ΒΎ
The fractions β and β΅βββ are equivalent.
Because,
β = β½ΒΉΛ£β΅βΎβββββ β = β΅βββ
Problem 5 :
Find the missing numbers :
β΅ββ = Β³β΅β? = ?βββ
Solution :
The numerator of the first two fractions are 5 and 35. And 5 will become 35, when we multiply 5 by 7.
So, we have to multiply the denominator of the first fraction 9 by 7 in order to get the denominator of the second fraction.
9x7 = 63
Hence, the denominator of the second fraction is 63.
The denominator of the first and third fraction are 9 and 72. And 9 will become 72, when we multiply by 8.
So, we have to multiply the numerator of the first fraction 5 by 8 in order to get the numerator of the third fraction.
Hence, the numerator of the third fraction is 40.
β΅ββ = Β³β΅βββ = β΄β°βββ
Problem 6 :
Find the missing numbers :
β = Β²ΒΉβ? = ?βββ
Solution :
The numerator of the first two fractions are 3 and 21. And 3 will become 21, when we multiply by 7.
So, we have to multiply the denominator of the first fraction 5 by 7 in order to get the denominator of the second fraction.
Hence, the denominator of the second fraction is 35.
The denominator of the first and third fraction are 5 and 20. And 5 will become 20, when we multiply by 4.
So, we have to multiply the numerator of the first fraction 3 by 4 in order to get the numerator of the third fraction.
Hence, the numerator of the third fraction is 12.
β = Β²ΒΉβββ = ΒΉΒ²βββ
Problem 7 :
If the following two fractions are equivalent, find the value of x.
βΉββ and Λ£ββ β
Solution :
Since βΉββ and Λ£ββ β are equivalent fractions,
βΉββ = Λ£ββ β
The denominator on the right side is 56. In the fraction βΉββ, the denominator is 8. To get an equivalent fraction with denominator 56, we have to multiply both numerator and denominator of the fraction βΉββ by 7.
β½βΉΛ£β·βΎββββββ = Λ£βββ
βΆΒ³ββ β = Λ£βββ
The above two fractions are equivalent with the same denominator. Then, the numerators must be equal.
Therefore,
x = 63
Problem 8 :
If the following two fractions are equivalent, find the value of y.
β»βΆβββ and ΚΈββ
Solution :
Since β»βΆβββ and ΚΈββ are equivalent fractions,
β»βΆβββ = ΚΈββ
The denominator on the left side is 3. In the fraction β»βΆβββ, the denominator is 18. To get an equivalent fraction with denominator 3, we have to divide both numerator and denominator of the fraction β»βΆβββ by 6.
β»β½βΆΓ·βΆβΎββββΓ·ββ = ΚΈββ
β»ΒΉββ = ΚΈββ
The above two fractions are equivalent with the same denominator. Then, the numerators must be equal.
Therefore,
y = -1
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