# DIVIDING POLYNOMIALS USING LONG DIVISION

## About "Dividing polynomials using long division"

Dividing polynomials using long division :

The division of polynomials p(x) and g(x) is expressed by the following “division algorithm” of algebra.

Let p(x) and g(x) be two polynomials such that degree of p(x)  degree of g(x) and g(x)  0. Then there exists unique polynomials q(x) and r (x)

such that

p(x) = g(x) q(x) + r (x) ... (1)

where r (x) = 0 or degree of r (x) < degree of g(x) .

The polynomial p(x) is the dividend, g(x) is the divisor, q(x) is the quotient and r (x) is the remainder.

(1) ==> Dividend = (Divisor x Quotient) + Remainder

Example 1 :

Divide the polynomial 2x³ - 6x² + 5x + 4 by (x - 2)

Solution :

Let P(x) = 2x³ - 6x² + 5x + 4 and g(x) = x - 2

To divide the given polynomial by x - 2, we have divide the first term of the polynomial P(x) by the first term of the polynomial g(x).

If we divide 2x³ by x, we get 2x². Now we have to multiply this 2x² by x - 2. From this we get 2x³ - 4x².

Now we have to subtract 2x³ - 4x² from the given polynomial. So we get -2x² + 5x + 4. Now we have to subtract 2x³ - 4x² from the given polynomial. So we get -2x² + 5x + 4.

repeat this process until we get the degree of p(x)  degree of g(x)  Hence the quotient = 2x² - 2x + 1 and remainder = 6

Example 2 :

Find the quotient and remainder when 4x³ - 5x² + 6x - 2 by x - 1.

Solution : Hence the quotient = 4x² - x + 5 and remainder = 3

Example 3 :

Find the quotient and remainder when x³ - 7x² - x + 6 by x + 2.

Solution : Hence the quotient = x² - 9x + 17 and remainder = -28

Example 4 :

Find the quotient and the remainder when (10- 4x + 3x²) is divided by x - 2.

Solution :

Let us first write the terms of each polynomial in descending order ( or ascending order).

Thus, the given problem becomes (10- 4x + 3x²) ÷ (x - 2)

f(x)  =  10- 4x + 3x²

=  3x² - 4x + 10

g (x) = x - 2

Step 1 :

In the first step, we are going to divide the first term of the dividend by the first first term of the divisor. After changing the signs, +3x² and - 3x² will get canceled. By simplifying we get 2x + 10

Step 2 :

In the second step again we are going to divide the first term that is 2x by the first term of divisor that is x. Quotient  =  3x + 2

Remainder  =  14

After having gone through the stuff given above, we hope that the students would have understood "Dividing polynomials using long division".

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