DIRECT VARIATION AND INVERSE VARIATION
Direct Variation
Please look at the following situations.
You buy more pens -----> Costs you more
More no. of students -----> More no. of teachers
Travel less distance -----> Time taken is less
No. of books reduced -----> Weight of bag is less
Thus we can say, if an increase in one quantity produces a proportionate increase in another quantity, then the quantities are said to be in direct variation.
or
If a decrease in one quantity produces a proportionate decrease in another quantity, then the quantities are said to be in direct variation.
Change in both the quantities must be same.
That is,
Increase -----> Increase
or
Decrease -----> Decrease
Inverse Variation
Please look at the following situations.
More men -----> Less days to complete a work
More speed -----> Less time to cover the distance
More vehicles on the road -----> Less road space
Less time per day -----> More days to complete the work
Thus we can say, if an increase in one quantity produces a proportionate decrease in another quantity, then the quantities are said to be in inverse variation.
or
If a decrease in one quantity produces a proportionate increase in another quantity, then the quantities are said to be in inverse variation.
Changes in the quantities must be opposite.
That is,
Increase -----> Decrease
or
Decrease -----> Increase
Shortcuts
Solved Problems
Problem 1 :
75 basketballs cost $1143.75. Find the cost of 26 basketballs.
Solution :
This is a situation of direct variation.
Because,
less number of basket balls -----> cost will be less
Let "m" be the cost of 26 basket balls.
|
No. of Basket Balls 75 26 |
Cost 1143.75 m |
Since this is direct variation, we have to apply the shortcut "cross multiplication"
75 ⋅ m = 26 ⋅ 1143.75
m = (26 ⋅ 1143.75) / 75
m = 396.50
So, the cost of 26 basket balls is $ 396.50
Problem 2 :
7 men can complete a work in 52 days. In how many days will 13 men finish the same work?
Solution :
This is a situation of inverse variation.
Because,
more men -----> less days
Let "m" be the required no. of days.
|
No. of Men 7 13 |
No. of Days 52 m |
Since this is inverse variation, we have to apply the shortcut "straight multiplication"
7 ⋅ 52 = 13 ⋅ m
(7 ⋅ 52) / 13 = m
28 = m
So, 13 men can complete the work in 28 days.
Problem 3 :
A book contains 120 pages and each page has 35 lines. How many pages will the book contain if every page has 24 lines per page ?
Solution :
This is a situation of inverse variation.
Because,
less lines -----> more pages
Let "m" be the required number of pages.
|
No. of Pages 120 m |
No. of Lines 35 24 |
Since this is inverse variation, we have to apply the shortcut "straight multiplication"
120 ⋅ 35 = m ⋅ 24
(120 ⋅ 35) / 24 = m
175 = m
So, if every page has 24 lines per page, the book will contain 175 pages.
Problem 4 :
A truck covers a particular distance in 3 hours with the speed of 60 miles per hour. If the speed is increased by 30 miles per hour, find the time taken by the truck to cover the same distance
Solution :
This is a situation of inverse variation.
Because,
more speed -----> less time
If the given speed 60 mph is increased by 30 mph,
then the new speed = 90 mph
Let "m" be the required time
|
No. of Hours 3 m |
Speed 60 90 |
Since this is inverse variation, we have to apply the shortcut "straight multiplication"
3 ⋅ 60 = m ⋅ 90
(3 ⋅ 60) / 90 = m
2 = m
So, if the speed is increased by 30 mph, time taken by the truck is 2 hours.
Problem 5 :
In a business, if A can earn $7500 in 2.5 years, At the same rate, find his earning for 4 years.
Solution :
This is a situation of direct variation.
Because,
more time -----> more earning
|
No. of Years 2.5 4 |
Earning 7500 m |
Since this is direct variation, we have to apply the shortcut "cross multiplication"
2.5 ⋅ m = 4 ⋅ 7500
m = (4 ⋅ 7500) / 2.5
m = 12000
So, the earning for 4 years is $12000.
Problem 6 :
In 36.5 weeks, Miguel raised $2,372.50 for cancer research. How much money will he raise 20 weeks ?
Solution :
This is a situation of direct variation.
Because,
less number of weeks ----> amount raised will be less
Let "m" be the required amount of money.
|
Weeks 36.5 20 |
Amount of Money 2372.50 m |
Since this is direct variation, we have to apply the shortcut "cross multiplication"
36.5 ⋅ m = 20 ⋅ 2372.50
m = (20 ⋅ 2372.50) / 36.5
m = 1300
So, the money raised in 20 weeks is $1300.
Problem 7 :
Alex takes 15 days to reduce 30 kilograms of his weight by doing 30 minutes exercise per day. If he does exercise for 1 hour 30 minutes per day, how many days will he take to reduce the same weight ?
Solution :
This is a situation of inverse variation.
Because,
more minutes per day----> less days to reduce the weight
And also
1 hour 30 minutes per day = 90 minutes per day
Let "m" be the required number of days.
|
No. of Days 15 m |
No. of Minutes 30 90 |
Since this is inverse variation, we have to apply the shortcut "straight multiplication"
15 ⋅ 30 = m ⋅ 90
(15 ⋅ 30) / 90 = m
5 = m
So, if Alex does exercise for 1 hour 30 minutes per day, it will take 5 days to reduce 30 kilograms of weight.
Problem 8 :
If 5 men can paint a house in 18 hours, how many men will be able to paint it in 10 hours ?
Solution :
This is a situation of inverse variation.
Because,
less hours -----> more men
Let "m" be the required number of men.
|
No. of Men 5 m |
No. of Hours 18 10 |
Since this is inverse variation, we have to apply the shortcut "straight multiplication"
5 ⋅ 18 = m ⋅ 10
90 / 10 = m
9 = m
So, 9 men will be able to paint the house in 10 hours.
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WORD PROBLEMS
Word problems on simple equations
Word problems on linear equations
Word problems on quadratic equations
Area and perimeter word problems
Word problems on direct variation and inverse variation
Word problems on comparing rates
Converting customary units word problems
Converting metric units word problems
Word problems on simple interest
Word problems on compound interest
Word problems on types of angles
Complementary and supplementary angles word problems
Trigonometry word problems
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Word problems on mixed fractrions
One step equation word problems
Linear inequalities word problems
Ratio and proportion word problems
Word problems on sets and venn diagrams
Pythagorean theorem word problems
Percent of a number word problems
Word problems on constant speed
Word problems on average speed
Word problems on sum of the angles of a triangle is 180 degree
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Domain and range of rational functions with holes
Graphing rational functions with holes
Converting repeating decimals in to fractions
Decimal representation of rational numbers
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L.C.M method to solve time and work problems
Translating the word problems in to algebraic expressions
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