We know the derivative of lnx, which is ¹⁄ₓ.
(lnx)' = ¹⁄ₓ
We can find the derivative of √sinx using chain rule.
If y = √lnx, find ᵈʸ⁄dₓ.
Let t = lnx.
Then, we have
y = √t
By chain rule,
Substitute t = lnx.
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