DERIVATIVE OF SQUARE ROOT OF LNX

We know the derivative of lnx, which is ¹⁄ₓ.

(lnx)' = ¹⁄ₓ

We can find the derivative of √sinx using chain rule.

If y = √lnx, find ᵈʸ⁄dₓ.

Let t = lnx.

Then, we have

y = √t

By chain rule,

Substitute t = lnx.

Therefore,

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