We know the derivative of lnx, which is ¹⁄ₓ. And also, the derivative secx is secxtanx.
(lnx)' = ¹⁄ₓ
(secx)' = secxtanx
We can find the derivative of ln(secx) using chain rule.
If y = ln(secx), find ᵈʸ⁄dₓ.
Let t = secx.
Then, we have
y = lnt
By chain rule,
Substitute y = lnt and t = secx.
Substitute t = secx.
Therefore,
Kindly mail your feedback to v4formath@gmail.com
We always appreciate your feedback.
©All rights reserved. onlinemath4all.com
Jul 13, 25 09:51 AM
Jul 13, 25 09:32 AM
Jul 11, 25 08:34 AM