DERIVATIVE OF NATURAL LOG OF COSX

We know the derivative of lnx, which is ¹⁄ₓ. And also, the derivative sinx is cosx.

(lnx)' = ¹⁄ₓ

(cosx)' = -sinx

We can find the derivative of ln(cosx) using chain rule.

If y = ln(cosx), find ᵈʸ⁄dₓ.

Let t = cosx.

Then, we have

y = lnt

By chain rule,

Substitute y = lnt and t = cosx.

Substitute t = cosx.

Therefore,

Kindly mail your feedback to v4formath@gmail.com

We always appreciate your feedback.